In a [member] table, some rows have the same value for the email
column.
login_id | email
---------|---------------------
john | john123@hot
Get the entire record as you want using the condition with inner select query.
SELECT *
FROM member
WHERE email IN (SELECT email
FROM member
WHERE login_id = abcd.user@hotmail.com)
This query will give you a list of email addresses and how many times they're used, with the most used addresses first.
SELECT email,
count(*) AS c
FROM TABLE
GROUP BY email
HAVING c > 1
ORDER BY c DESC
If you want the full rows:
select * from table where email in (
select email from table
group by email having count(*) > 1
)
use this if your email column contains empty values
select * from table where email in (
select email from table group by email having count(*) > 1 and email != ''
)
Here is query to find email
's which are used for more then one login_id
:
SELECT email
FROM table
GROUP BY email
HAVING count(*) > 1
You'll need second (of nested) query to get list of login_id
by email
.
Thanks guys :-) I used the below because I only cared about those two columns and not so much about the rest. Worked great
select email, login_id from table
group by email, login_id
having COUNT(email) > 1
First part of accepted answer does not work for MSSQL.
This worked for me:
select email, COUNT(*) as C from table
group by email having COUNT(*) >1 order by C desc