How to iterate over a JavaScript object?

Question

I have an object in JavaScript:

{
    abc: \'...\',
    bca: \'...\',
    zzz: \'...\',
    xxx: \'...\',
    ccc: \'...\',
    // ...
}

I

Answer 1

->if we iterate over a JavaScript object using and find key of array of objects

Object.keys(Array).forEach(key => {

 console.log('key',key)

})

Answer 2

Using Object.entries you do something like this.

 // array like object with random key ordering
 const anObj = { 100: 'a', 2: 'b', 7: 'c' };
 console.log(Object.entries(anObj)); // [ ['2', 'b'],['7', 'c'],['100', 'a'] ]

The Object.entries() method returns an array of a given object's own enumerable property [key, value]

So you can iterate over the Object and have key and value for each of the object and get something like this.

const anObj = { 100: 'a', 2: 'b', 7: 'c' };
Object.entries(anObj).map(obj => {
   const key   = obj[0];
   const value = obj[1];

   // do whatever you want with those values.
});

or like this

// Or, using array extras
Object.entries(obj).forEach(([key, value]) => {
  console.log(`${key} ${value}`); // "a 5", "b 7", "c 9"
});

For a reference have a look at the MDN docs for Object Entries

Answer 3

You can try using lodash- A modern JavaScript utility library delivering modularity, performance & extras js to fast object iterate:-

var  users  =   {
    'fred':     { 
        'user':   'fred',
            'age':  40 
    },
    'pebbles':  { 
        'user':   'pebbles',
         'age':  1 
    }
}; 
_.mapValues(users,  function(o)  { 
    return  o.age; 
});
// => { 'fred': 40, 'pebbles': 1 } (iteration order is not guaranteed)
// The `_.property` iteratee shorthand.
console.log(_.mapValues(users,  'age')); // returns age property & value 
console.log(_.mapValues(users,  'user')); // returns user property & value 
console.log(_.mapValues(users)); // returns all objects 
// => { 'fred': 40, 'pebbles': 1 } (iteration order is not guaranteed)

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash-compat/3.10.2/lodash.js"></script>

Answer 4

var Dictionary = {
  If: {
    you: {
      can: '',
      make: ''
    },
    sense: ''
  },
  of: {
    the: {
      sentence: {
        it: '',
        worked: ''
      }
    }
  }
};

function Iterate(obj) {
  for (prop in obj) {
    if (obj.hasOwnProperty(prop) && isNaN(prop)) {
      console.log(prop + ': ' + obj[prop]);
      Iterate(obj[prop]);
    }
  }
}
Iterate(Dictionary);

Answer 5

Here is a Hand Made Solution:

function iterationForObject() {
    let base = 0,
        Keys= Object.keys(this);
    return {
        next: () => {
            return {
                value: {
                    "key": Keys[base],
                    "value": this[Keys[base]]
                },
                done: !(base++ < Keys.length)
            };
        }
    };
}
Object.prototype[Symbol.iterator] = iterationForObject;

And Then You Can Loop Any Object:

for ( let keyAndValuePair of (Object Here) ) {
    console.log(`${keyAndValuePair.key} => ${keyAndValuePair.value}`);
}

Answer 6

With the new ES6/ES2015 features, you don't have to use an object anymore to iterate over a hash. You can use a Map. Javascript Maps keep keys in insertion order, meaning you can iterate over them without having to check the hasOwnProperty, which was always really a hack.

Iterate over a map:

var myMap = new Map();
myMap.set(0, "zero");
myMap.set(1, "one");
for (var [key, value] of myMap) {
  console.log(key + " = " + value);
}
// Will show 2 logs; first with "0 = zero" and second with "1 = one"

for (var key of myMap.keys()) {
  console.log(key);
}
// Will show 2 logs; first with "0" and second with "1"

for (var value of myMap.values()) {
  console.log(value);
}
// Will show 2 logs; first with "zero" and second with "one"

for (var [key, value] of myMap.entries()) {
  console.log(key + " = " + value);
}
// Will show 2 logs; first with "0 = zero" and second with "1 = one"

or use forEach:

myMap.forEach(function(value, key) {
  console.log(key + " = " + value);
}, myMap)
// Will show 2 logs; first with "0 = zero" and second with "1 = one"