Get a list of numbers as input from the user

Question

I tried to use raw_input() to get a list of numbers, however with the code

numbers = raw_input()
print len(numbers)

the input

Answer 1

k = []
i = int(raw_input('enter the number of values in the list '))
l = 0
while l < i:
    p = raw_input('enter the string ')
    k.append(p)
    l= l+1


print "list is ", k

Answer 2

It is much easier to parse a list of numbers separated by spaces rather than trying to parse Python syntax:

Python 3:

s = input()
numbers = list(map(int, s.split()))

Python 2:

s = raw_input()
numbers = map(int, s.split())

Answer 3

try this one ,

n=int(raw_input("Enter length of the list"))
l1=[]
for i in range(n):
    a=raw_input()
    if(a.isdigit()):
        l1.insert(i,float(a)) #statement1
    else:
        l1.insert(i,a)        #statement2

If the element of the list is just a number the statement 1 will get executed and if it is a string then statement 2 will be executed. In the end you will have an list l1 as you needed.

Answer 4

You can use this function (with int type only) ;)

def raw_inputList(yourComment):
     listSTR=raw_input(yourComment)     
     listSTR =listSTR[1:len(listSTR)-1]
     listT = listSTR.split(",")
     listEnd=[]
     for caseListT in listT:
          listEnd.append(int(caseListT))
     return listEnd

This function return your list (with int type) !

Example :

yourList=raw_inputList("Enter Your List please :")

If you enter

"[1,2,3]" 

then

yourList=[1,2,3]          

Answer 5

Another way could be to use the for-loop for this one. Let's say you want user to input 10 numbers into a list named "memo"

memo=[] 
for i in range (10):
    x=int(input("enter no. \n")) 
    memo.insert(i,x)
    i+=1
print(memo)