In SQL Server how do I generate an auto-increment primary key ID that consists of year , a special char and a sequential series no.?

Question

I am encountering this kind of advance SQL coding task like generating an auto-increment primary key ID that consists of a year, a special char and a sequential seri

Answer 1

Here is a complete solution. Please note that it's exactly the same as the duplicate I've marked - Database scheme, autoincrement - Just different details.

CREATE TABLE [dbo].[STUDENT]
(
    [ID] int identity(1,1) PRIMARY KEY,
    [Stud_LName] [varchar](100) NOT NULL,
    [Stud_FName] [varchar](100) NOT NULL,
    [Stud_MName] [varchar](100) NOT NULL
)
GO

CREATE FUNCTION dbo.GetSudentId
(
    @id int
)
RETURNS varchar(10)
AS
BEGIN
    RETURN Concat(Year(Getdate()), '-', RIGHT(Concat('0000', (SELECT COUNT(*) FROM STUDENT WHERE id < @Id)), 6))
END
GO

ALTER TABLE [dbo].[STUDENT]
    ADD Stud_ID AS (dbo.GetSudentId(Id))
GO

Please note that the primary key of the table must still be the identity column (as shown in the script) since the computed column can't be the primary key.

Answer 2

You should go through Computed column, which helps to manage your design. Please refer below example.

CREATE TABLE #test(id INT IDENTITY(1,1) PRIMARY KEY, 
Stud_ID AS CAST(YEAR(GETDATE()) as VARCHAR(4)) +'-'+ REPLICATE('0', 5 - DATALENGTH(CAST(id as VARCHAR(10))))+ CAST(id as VARCHAR(10)), 
Stud_LName VARCHAR(100), 
Stud_FName VARCHAR(100), 
Stud_MName VARCHAR(100)
)


INSERT INTO #test(Stud_LName, Stud_FName, Stud_MName)
values
('lname_1' , 'fname 1', 'mname 1'),
('lname_2' , 'fname 2', 'mname 2'),
('lname_3' , 'fname 3', 'mname 3'),
('lname_4' , 'fname 4', 'mname 4'),
('lname_5' , 'fname 5', 'mname 5'),
('lname_6' , 'fname 6', 'mname 6'),
('lname_7' , 'fname 7', 'mname 7'),
('lname_8' , 'fname 8', 'mname 8'),
('lname_9' , 'fname 9', 'mname 9'),
('lname_10', 'fname 10', 'mname 10')


select * from #test;


DROP TABLE #test;