Sort an array of objects by multiple properties

Question

I have an array of objects like this:

var a = [
    { id: 1, score: 1, isCut: false, dnf: false },
    { id: 2, score: 2, isCut: false, dnf: false },
    { i         


        

Answer 1

This is a different approach, which uses an array for the sort order, which is irregular, if using dnf and isCut property without looking at both. If we take a both values to a truth table, then the sort order does not reflect the wanted order.

                   2*dnf+isCut
    dnf     isCut     value     order
--------  --------  --------  --------
     0         0         0         0
     0         1         1         1
     1         1         3         2
     1         0         2         3

To correct the sort order, I suggest to use an array for getting the right order.

var data = [{ id: 1, score: 1, isCut: false, dnf: false }, { id: 2, score: 2, isCut: false, dnf: false }, { id: 3, score: 3, isCut: false, dnf: false }, { id: 4, score: 4, isCut: false, dnf: false }, { id: 5, score: 5, isCut: true, dnf: true }, { id: 6, score: 6, isCut: true, dnf: false }, { id: 7, score: 7, isCut: true, dnf: false }, { id: 8, score: 8, isCut: true, dnf: false }, { id: 9, score: 9, isCut: true, dnf: false }, { id: 10, score: 0, isCut: false, dnf: false }, { id: 11, score: -1, isCut: false, dnf: false }, { id: 12, score: -2, isCut: false, dnf: true }, { id: 13, score: -3, isCut: false, dnf: false }, { id: 14, score: -4, isCut: false, dnf: false }, { id: 15, score: -5, isCut: false, dnf: false }, { id: 16, score: 10, isCut: true, dnf: false }];

data.sort(function (a, b) {
    function order(dnf, isCut) { return [0, 1, 3, 2][dnf * 2 + isCut]; }

    return order(a.dnf, a.isCut) - order(b.dnf, b.isCut) || b.score - a.score;
});

console.log(data);

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Answer 2

Use comparator function from Array

you can check answers here : Sort array of objects by string property value in JavaScript

Answer 3

(Updated) Here's the answer of question you mentioned in comment.

a.sort(function(a, b) {
  if (a.dnf != b.dnf) {
    return a.dnf ? 1 : -1;
  }
  if (!(a.dnf && b.dnf) && a.isCut != b.isCut) {
    return a.isCut ? 1 : -1;
  }
  if (a.score != b.score) {
    return b.score - a.score; // descending
  }
  return b.id - a.id; // descending
});

Result:

[
  {"id":4,"score":4,"isCut":false,"dnf":false},   // the rest: order by score, id
  {"id":3,"score":3,"isCut":false,"dnf":false},   //
  {"id":2,"score":2,"isCut":false,"dnf":false},   //
  {"id":1,"score":1,"isCut":false,"dnf":false},   //
  {"id":10,"score":0,"isCut":false,"dnf":false},  //
  {"id":11,"score":-1,"isCut":false,"dnf":false}, //
  {"id":13,"score":-3,"isCut":false,"dnf":false}, //
  {"id":14,"score":-4,"isCut":false,"dnf":false}, //
  {"id":15,"score":-5,"isCut":false,"dnf":false}, //
  {"id":16,"score":10,"isCut":true,"dnf":false}, // isCut: order by score, id
  {"id":9,"score":9,"isCut":true,"dnf":false},   //
  {"id":8,"score":8,"isCut":true,"dnf":false},   //
  {"id":7,"score":7,"isCut":true,"dnf":false},   //
  {"id":6,"score":6,"isCut":true,"dnf":false},   //
  {"id":5,"score":5,"isCut":true,"dnf":true},   // dnf: order by score, id
  {"id":12,"score":-2,"isCut":false,"dnf":true} //
]

Answer 4

You can do it in one line with Alasql library:

var res = alasql('SELECT * FROM ? ORDER BY dnf, isCut, score, id',[a]);