checking if a number is float in PHP

Question

This is really weird. I have this piece of code.

$rewardAmt = $amt;
if(is_float($rewardAmt)){
      print_r(\"is float\");die;
} else {
      print_r(\"is no         


        

Answer 1

You can check this by

$float = floatval($num); //Convert the string to a float
if($float && intval($float) != $float) // Check if the converted int is same as the float value...
{
    // $num is a float
}else{
    // $num is an integer
}

Answer 2

If you change the first line to

$rewardAmt = $amt+0;

$rewardAmt should be cast to a number.

Answer 3

Use filter_var() with FILTER_VALIDATE_FLOAT

if (filter_var($amount, FILTER_VALIDATE_FLOAT))
{
     // good
}

Answer 4

You can use the unary + operator, which will cast the string to the appropriate type (int or float), and then test the resulting data type with is_float:

$s = "3.00";
$n = +$s;
var_dump( $n ); // float(3)
var_dump( is_float($n) ); // true


$s = "3";
$n = +$s;
var_dump( $n ); // int(3)
var_dump( is_float($n) ); // false