Python list comprehension overriding value

后端 未结 4 1518
小蘑菇
小蘑菇 2020-11-30 13:58

have a look at the following piece of code, which shows a list comprehension..

>>> i = 6
>>> s = [i * i for i in range(100)]
>>> p         


        
相关标签:
4条回答
  • 2020-11-30 14:09

    Yes, there is a reason, and the reason is that they didn't want the temporary variable in a list comprehension to leak into the outer namespace. So it is an intentional change that is a result of list comprehensions now being syntactic sugar for passing a generator expression to list().

    Ref: PEP3100.

    0 讨论(0)
  • 2020-11-30 14:14

    The old behaviour was a mistake but couldn't easily be fixed as some code relied on it.

    The variable i inside the list comprehension should be a different i from the one at the top level. Logically it should have its own scope which does not extend outside the comprehension as its value only makes sense inside the comprehension. But in Python 2.x due to an implementation detail the scope was larger than necessary causing the variable to "leak" into the outer scope, causing the confusing results you see.

    Python 3.0 was deliberately not intended to be backwards compatible with previous releases, so they used the opportunity to fix this undesirable behaviour.

    In Python 2.3 and later releases, a list comprehension “leaks” the control variables of each for it contains into the containing scope. However, this behavior is deprecated, and relying on it will not work in Python 3.0

    Source

    0 讨论(0)
  • 2020-11-30 14:26

    Looks like a change in scoping to me.

    I confirmed your result in Python 2.6; it does indeed print 99, which is the last value assigned to i in the list comprehension.

    0 讨论(0)
  • 2020-11-30 14:30

    Mark Byers answered it perfectly.

    just as a side note..
    in Python 2.x, if you change your brackets to parens (creating a generator expression instead of a list comprehension), you will notice that the control variable is not leaked.

    >>> i = 6
    >>> s = (i for i in range(100))
    >>> print i
    6
    

    vs.

    >>> i = 6
    >>> s = [i for i in range(100)]
    >>> print i
    99
    

    (of course, in Python 3, this is fixed and list comprehensions no longer leak control variables)

    0 讨论(0)
提交回复
热议问题