`Double.ToString` with N number of decimal places [duplicate]

Answer 1

Use "Nx" for x decimal digits.

 public void DisplayNDecimal(double dbValue, int nDecimal)
 {
   Console.WriteLine(dbValue.ToString("N" + nDecimal));
 }

Answer 2

I would use this:

public string DisplayNDecimal(double dbValue, int nDecimal)
{
    string decimalPoints = "0";
    if (nDecimal > 0)
    {
        decimalPoints += ".";
        for (int i = 0; i < nDecimal; i++)
            decimalPoints += "0";
    }
    return dbValue.ToString(decimalPoints);
}

:)

Here is it with StringBuilder (though probably not more efficient and definitely would require more resources)

public string DisplayNDecimal(double dbValue, int nDecimal)
{
    StringBuilder decimalPoints = new StringBuilder("0");
    if (nDecimal > 0)
    {
        decimalPoints.Append(".");
        for (int i = 0; i < nDecimal; i++)
            decimalPoints.Append("0");
    }
    return dbValue.ToString(decimalPoints.ToString());
}