Returning Multiple Rows with MySqli and Arrays

Question

For the past two days or so I\'ve been converting my functions to mysqli. I\'ve run into a problem. I have a function that returns an array containing a row from the databas

Answer 1

You have to use a loop to get them all at once:

<?php
function resultToArray($result) {
    $rows = array();
    while($row = $result->fetch_assoc()) {
        $rows[] = $row;
    }
    return $rows;
}

// Usage
$query = 'SELECT DISTINCT $fields FROM `posts` WHERE `profile_user_id` = $user_id LIMIT 4';
$result = $mysqli->query($query);
$rows = resultToArray($result);
var_dump($rows); // Array of rows
$result->free();

Answer 2

I'm late, but I believe this is what you wanted to achieve:

$mysqli = new mysqli("localhost", "user", "password", "database");
$fields = "`primary_id`, `poster_id`, `profile_user_id`, `post`";

function display_posts () {

    global $mysqli;
    global $fields;

    $query = "SELECT DISTINCT $fields FROM `posts` WHERE `profile_user_id` = $user_id LIMIT 4";

    $posts = $mysqli -> query($query) or die('Error: '.$mysqli -> error);

    if ($posts -> num_rows > 0) {

        while ($row = $posts -> fetch_assoc()) {

        $value = $row['/*The table column here (You can repeat this line with a different variable e.g. $value 2, $value 3 etc and matching them with the respective table column)*/'];

        echo $value./*Concatenate the other variables ($value 1 etc) here*/'<br />';

        }

    }else {

        echo 'No records found.';

    }

}

//Call the function
display_posts ();

Answer 3

Why not use directly like this:

$result = mysqli_fetch_all($mysqli->query($query), MYSQLI_ASSOC);