java urlconnection get the final redirected URL

Question

I have a url which redirects to another url.I want to be able to get the final redirected URL.My code:

    public class testURLConnection
    {
    public st         


        

Answer 1

Try this, I using recursively to using for many redirection URL.

public static String getFinalURL(String url) throws IOException {
    HttpURLConnection con = (HttpURLConnection) new URL(url).openConnection();
    con.setInstanceFollowRedirects(false);
    con.connect();
    con.getInputStream();

    if (con.getResponseCode() == HttpURLConnection.HTTP_MOVED_PERM || con.getResponseCode() == HttpURLConnection.HTTP_MOVED_TEMP) {
        String redirectUrl = con.getHeaderField("Location");
        return getFinalURL(redirectUrl);
    }
    return url;
}

and using:

public static void main(String[] args) throws MalformedURLException, IOException {
    String fetchedUrl = getFinalURL("<your_url_here>");
    System.out.println("FetchedURL is:" + fetchedUrl);

}

Answer 2

This might help

public static void main(String[] args) throws MalformedURLException,
    IOException {

HttpURLConnection con = (HttpURLConnection) new URL(
        "http://tinyurl.com/KindleWireless").openConnection(proxy);
    System.out.println("orignal url: " + con.getURL());
    con.connect();
    con.setInstanceFollowRedirects(false);
    int responseCode = con.getResponseCode();
    if ((responseCode / 100) == 3) {
        String newLocationHeader = con.getHeaderField("Location");
        responseCode = con.getResponseCode();
        System.out.println("Redirected Location " + newLocationHeader);
        System.out.println(responseCode);
    }

}

Answer 3

@JEETS Your fetchRedirectURL function may not work because there are a variety of HTTP codes for redirects. Change it to a range check and it will work.

public static String fetchRedirectURL(String url) throws IOException
    {
HttpURLConnection con =(HttpURLConnection) new URL( url ).openConnection();
//System.out.println( "orignal url: " + con.getURL() );
con.setInstanceFollowRedirects(false);
con.connect();

InputStream is = con.getInputStream();
if(con.getResponseCode()>=300 && con.getResponseCode() <400)
    return con.getHeaderField("Location");
else return null;
    }

Answer 4

public static String getFinalRedirectedUrl(String url) {

    HttpURLConnection connection;
    String finalUrl = url;
    try {
        do {
            connection = (HttpURLConnection) new URL(finalUrl)
                    .openConnection();
            connection.setInstanceFollowRedirects(false);
            connection.setUseCaches(false);
            connection.setRequestMethod("GET");
            connection.connect();
            int responseCode = connection.getResponseCode();
            if (responseCode >= 300 && responseCode < 400) {
                String redirectedUrl = connection.getHeaderField("Location");
                if (null == redirectedUrl)
                    break;
                finalUrl = redirectedUrl;
                System.out.println("redirected url: " + finalUrl);
            } else
                break;
        } while (connection.getResponseCode() != HttpURLConnection.HTTP_OK);
        connection.disconnect();
    } catch (Exception e) {
        e.printStackTrace();
    }
    return finalUrl;
}

Answer 5

@user719950 On my MAC-OSX - this solves the issue of truncated HTTP URL :

To your original code , just add this below line : // You have to find through your browser what is the Request Header IE / Chrome is sending. I still dont have the explanation as why this simple setting is causing correct URL :)

HttpURLConnection con =(HttpURLConnection) new URL
( "http://tinyurl.com/KindleWireless" ).openConnection();
 con.setInstanceFollowRedirects(true);
 con.setDoOutput(true);
  System.out.println( "orignal url: " + con.getURL() );     
         **con.setRequestProperty("User-Agent",
    "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_2) 
    AppleWebKit/536.26.17 (KHTML, like Gecko) Version/6.0.2  
   Safari/536.26.17");**                  

           con.connect();
    System.out.println( "connected url: " + con.getURL() );
    Thread.currentThread().sleep(2000l);
    InputStream is = con.getInputStream();
    System.out.println( "redirected url: " + con.getURL() );

    is.close();

Answer 6

This one goes recursively in case there are multiple redirects:

protected String getDirectUrl(String link) {
    String resultUrl = link;
    HttpURLConnection connection = null;
    try {
        connection = (HttpURLConnection) new URL(link).openConnection();
        connection.setInstanceFollowRedirects(false);
        connection.connect();
        int responseCode = connection.getResponseCode();
        if (responseCode == HttpURLConnection.HTTP_MOVED_PERM || responseCode == HttpURLConnection.HTTP_MOVED_TEMP) {
            String locationUrl = connection.getHeaderField("Location");

            if (locationUrl != null && locationUrl.trim().length() > 0) {
                IOUtils.close(connection);
                resultUrl = getDirectUrl(locationUrl);
            }
        }
    } catch (Exception e) {
        log("error getDirectUrl", e);
    } finally {
        IOUtils.close(connection);
    }
    return resultUrl;
}