regex to match substring after nth occurence of pipe character

Question

i am trying to build one regex expression for the below sample text in which i need to replace the bold text. So far i could achieve this much ((\\|))

Answer 1

^((?:[^|]*\\|){3})[^|]+

You can use this.Replace by $1<anything>.See demo.

https://regex101.com/r/tP7qE7/4

This here captures from start of string to | and then captures 3 such groups and stores it in $1.The next part of string till | is what you want.Now you can replace it with anything by $1<textyouwant>.

Answer 2

To match part after nth occurrence of pipe you can use this regex:

/^(?:[^|]*\|){3}([^|]*)/

Here n=3

It will match 10.15.194.25 in matched group #1

RegEx Demo

Answer 3

Here's how you can do the replacement:

String input = "1.1|ProvCM|111111111111|10.15.194.25|10.100.10.3|10.100.10.1|docsis3.0";
int n = 3;
String newValue = "new value";
String output = input.replaceFirst("^((?:[^|]+\\|){"+n+"})[^|]+", "$1"+newValue);

This builds:

"1.1|ProvCM|111111111111|new value|10.100.10.3|10.100.10.1|docsis3.0"