How to destructure option argument with all default values in ES6?

Question

I use ES6 features with babel compiler. I have a function which takes option object as an argument:

function myFunction({ option1 = true, option2 = \'whateve         


        

Answer 1

Yes, you just have to provide a default value for the complete argument:

function myFunction({option1 = true, option2 = 'whatever'} = {}) {
//                                                         ^^^^
    console.log(option1, option2);
    // do something...
}