Custom type passed to function as a parameter

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悲&欢浪女
悲&欢浪女 2020-11-30 11:38

When I define a custom type, it seems that the type of the underlying type makes a difference about whether I can pass it to a function as is or I need to convert it.

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  • 2020-11-30 12:04

    Integer and int

    int and your new type Integer are 2 different, distinct types. Where Integer is expected, you have to pass a value of type Integer.

    If you have an Integer value, you may use a simple type conversion to make it a value of type int, because the underlying type of Integer is int:

    var i Integer = 5
    nf(int(i))
    

    What may be confusing and interesting at the same time is that you are allowed to pass an untyped constant without conversion:

    nf(5)
    

    Try these on the Go Playground.

    The reason for this is in the Spec: Assignability:

    A value x is assignable to a variable of type T ("x is assignable to T") in any of these cases:

    [...]

    • x is an untyped constant representable by a value of type T.

    5 is an untyped constant which is representable by a value of type int because the untyped constant 5 has a default type int, so it is representable by a value of type Integer (which has the same default type).

    If you check the other assignability rules (not included in above quotation), none of them match the case where you attempt to pass a value of Integer for the parameter of type int, so that's not allowed.

    See related question: Golang: Creating a Constant Type and Restricting the Type's Values

    RuneFunc and func(rune) rune

    The difference between this case and the previous one (Integer and int) is that int is a named type and func(rune) rune is not.

    And there's an assignability rule which allows this:

    • x's type V and T have identical underlying types and at least one of V or T is not a named type.

    So in this case:

    var f RuneFunc
    ff(f)
    

    f is a named type, but the parameter type of ff() is func(rune) rune which is unnamed, so the assignment is allowed.

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  • 2020-11-30 12:19

    Go has a strict type system. Just because your type is merely an alias for int doesn't mean you can interchange the two freely, you'll still have to do a type conversion. Below is a working version of your main, here's the code on play ground: https://play.golang.org/p/BDTXnnG9Lg

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