PHP split string into integer element and string

Question

I have a string say: Order_num = \"0982asdlkj\"

How can I split that into the 2 variables, with the number element and then another variable with the le

Answer 1

Use preg_match() with a regular expression of (\d+)([a-zA-Z]+). If you want to limit the number of digits to 1-4 and letters to 6-9, change it to (\d+{1,4})([a-zA-Z]{6,9}).

preg_match("/(\\d+)([a-zA-Z]+)/", "0982asdlkj", $matches);
print("Integer component: " . $matches[1] . "\n");
print("Letter component: " . $matches[2] . "\n");

Outputs:

Integer component: 0982
Letter component: asdlkj

http://ideone.com/SKtKs

Answer 2

You can also do it using preg_split by splitting your input at the point which between the digits and the letters:

list($num,$alpha) = preg_split('/(?<=\d)(?=[a-z]+)/i',$Order_num);

See it

Answer 3

You can use a regex for that.

preg_match('/(\d{1,4})([a-z]+)/i', $str, $matches);
array_shift($matches);
list($num, $alpha) = $matches;

Answer 4

Check this out

<?php
$Order_num = "0982asdlkj";
$split=split("[0-9]",$Order_num);
$alpha=$split[(sizeof($split))-1];
$number=explode($alpha, $Order_num);
echo "Alpha -".$alpha."<br>";
echo "Number-".$number[0];
?>

with regards

wazzy

Answer 5

You can use preg_split using lookahead and lookbehind:

print_r(preg_split('#(?<=\d)(?=[a-z])#i', "0982asdlkj"));

prints

Array
(
    [0] => 0982
    [1] => asdlkj
)

This only works if the letter part really only contains letters and no digits.

Update:

Just to clarify what is going on here:

The regular expressions looks at every position and if a digit is before that position ((?<=\d)) and a letter after it ((?=[a-z])), then it matches and the string gets split at this position. The whole thing is case-insensitive (i).