Print a triangular pattern of asterisks

Question

I am required to use nested for loops and print(\'*\', end=\' \') to create the pattern shown here:

And here is my code. I have figured out the first t

Answer 1

print("Pattern C")
n=int(input("Enter number of rows: ")) 
for i in range (n,0,-1):
    print((n-i) * ' ' + i * '*')

Answer 2

Pythonic way of doing this. Just 1 line of code (using list comprehension) for each pattern.

n = 10

# for A
print('\n'.join(['*'*i for i in range(1,n+1)]))

#output
*
**
***
****
*****
******
*******
********
*********
**********


# for B
print('\n'.join(['*'*i for i in range(n+1,0,-1)]))

#output
***********
**********
*********
********
*******
******
*****
****
***
**
*

# for C
print('\n'.join([' '*(n-i) + '*'*i for i in range(n,0,-1)]))

#output
**********
 *********
  ********
   *******
    ******
     *****
      ****
       ***
        **
         *


# for D
print('\n'.join([' '*(n-i) + '*'*i for i in range(1,n+1)]))

#output
         *
        **
       ***
      ****
     *****
    ******
   *******
  ********
 *********
**********

Answer 3

using spaces you can create different- different patterns: 1.

def pattern(limit):

    for i in range(limit+1):
        print((limit-i)*"  "+ ' #'*i)    

pattern(4)

Output: 
       #
     # #
   # # #
 # # # #

2.remove one space from above code and pattern will be changed in a pyramid

def pattern(limit):
    for i in range(limit+1):
        print((limit-i)*" "+ ' #'*i)       
pattern(4)

output: #
       # #
      # # #
     # # # # 

3: no space print((limit-i)*""+ ' #'*i) will create

 #
 # #
 # # #
 # # # #

Answer 4

i=0
while(i<5):
    j=0
    while(j<=i):
        print("*",end="") #end="" is given to stay on same line
        j=j+1
    print("")  #it will take u to new line
    i=i+1
    j=0
i=i-2
j=i
while(i>=0):
    while(j>=0):
        print("*",end="")
        j=j-1
    print() #will also work
    i=i-1
    j=i

this will also work

Answer 5

learn an easy way:
code1:

for n in range(0,5):
    n +=1
    print ("*" *(0+n))

what it does:

1. for n in range(0,5): --> call a range of no of times you want loop to execute
2. increment value of int n by one, so starting from range 0 to 5 every time for loop runs it increments int n by 1
3. now print string "" and multiply it by value of int n+0, So when int n=0 as per logic int n increments by 1 and print ("" (0+n)) = print ("" *(0+1)) = *

output:
*
**
***
****
*****

code2:

for n in range(-5,0):
    n +=1
    print ("*" *(0-n+1))

output:
****
***
**
*

Answer 6

def fun (n):
    return n
n=int(raw_input("Enter the number"))
print "The given number is",n
for i in range (n,0,-1):
    print "*"*i

output:

The given number is 3
***
**
*