Conversion between character and int in Java

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我在风中等你
我在风中等你 2020-11-30 10:52

You cannot convert from int to char, so this would be illegal int i = 88; char c = i;,

However this is allowed char c = 88;.

Isn\'t

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  • 2020-11-30 11:12

    Actually, converting from int to char is legal, it just requires an explicit cast because it can potentially lose data:

    int i = 88; 
    char c = (char) i;
    

    However, with the literal, the compiler knows whether it will fit into a char without losing data and only complains when you use a literal that is too big to fit into a char:

    char c = 70000; // compiler error
    
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  • 2020-11-30 11:14

    char is effectively an unsigned 16-bit integer type in Java.

    Like other integer types, you can perform an assignment conversion from an integer constant to any integer type so long as it's in the appropriate range. That's why

    byte b = 10;
    

    works too.

    From the JLS, section 5.2:

    In addition, if the expression is a constant expression (§15.28) of type byte, short, char or int :

    • A narrowing primitive conversion may be used if the type of the variable is byte, short, or char, and the value of the constant expression is representable in the type of the variable.
    • A narrowing primitive conversion followed by a boxing conversion may be used if the type of the variable is :
      • Byte and the value of the constant expression is representable in the type byte.
      • Short and the value of the constant expression is representable in the type short.
      • Character and the value of the constant expression is representable in the type char.
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  • 2020-11-30 11:22

    Its because the literals for integer or smaller than int as byte ,short and char is int. Understand the following in this way.

    code:

      byte a = 10;//compile fine
      byte b= 11;//compile fine
      byte c = a+b;//compiler error[says that result of **a+b** is **int**]
    

    the same happens for any mathematical operations as of 'Divide', 'multiply', and other arithmetic operation. so cast the result to get the literal in desired data type

    byte c = (byte)(a+b);
    

    So that the same reason why the value int need to have primitive cast to change the value in char. Hope this make some sense.

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