Hey I have created a Groovy script that will extract the version numbers of some folder. I would then like to compare the version numbers and select the highest.
I g
If anyone is using Grails (e.g. Grails 2.2.3), I think VersionComparator already provides exactly what we need.
If you are not using Grails, you can always Google the source code of this class.
Example of working tests:
import org.codehaus.groovy.grails.plugins.VersionComparator
assert ['1.13.4', '1.4.5'].sort( new VersionComparator() ) == ['1.4.5', '1.13.4']
assert ['3.1.20', '3', '3.0.1', '3.1'].sort( new VersionComparator() ) == ['3', '3.0.1', '3.1', '3.1.20']
assert ['02.2.02.02', '02.2.03.01', '02.2.02.01'].sort( new VersionComparator() ) == ['02.2.02.01', '02.2.02.02', '02.2.03.01']
assert ['4', '2'].sort( new VersionComparator() ) == ['2', '4']
assert ['4.1', '4'].sort( new VersionComparator() ) == ['4', '4.1']
assert ['4.1', '5'].sort( new VersionComparator() ) == ['4.1', '5']
assert new VersionComparator().compare( '1.13.4', '1.4.5' ) > 0
assert new VersionComparator().compare( '1.4.5', '1.13.4' ) < 0
Hope this helps.
Here's a slightly modified version of Nikita's contribution:
List versions = [ '02.2.02.01', '02.2.02.02', '02.2.03.01']
String mostRecentVersion = versions.sort {a, b ->
def a1 = a.tokenize('.')*.toInteger(), b1 = b.tokenize('.')*.toInteger()
for (i in 0..<[a1.size(), b1.size()].min()){
if (a1[i] != b1[i]) {
return a1[i] <=> b1[i]
}
}
}[-1]
assert mostRecentVersion == '02.2.03.01'
If we're going for the shortest answer, this must come close ;-)
String mostRecentVersion( List versions ) {
versions.sort( false ) { a, b ->
[a,b]*.tokenize('.')*.collect { it as int }.with { u, v ->
[u,v].transpose().findResult{ x,y-> x<=>y ?: null } ?: u.size() <=> v.size()
}
}[-1]
}
This appears to work
String mostRecentVersion(List versions) {
def sorted = versions.sort(false) { a, b ->
List verA = a.tokenize('.')
List verB = b.tokenize('.')
def commonIndices = Math.min(verA.size(), verB.size())
for (int i = 0; i < commonIndices; ++i) {
def numA = verA[i].toInteger()
def numB = verB[i].toInteger()
println "comparing $numA and $numB"
if (numA != numB) {
return numA <=> numB
}
}
// If we got this far then all the common indices are identical, so whichever version is longer must be more recent
verA.size() <=> verB.size()
}
println "sorted versions: $sorted"
sorted[-1]
}
Here is an inadequate set of tests. You should add some more.
assert mostRecentVersion(['02.2.02.01', '02.2.02.02', '02.2.03.01']) == '02.2.03.01'
assert mostRecentVersion(['4', '2']) == '4'
assert mostRecentVersion(['4.1', '4']) == '4.1'
assert mostRecentVersion(['4.1', '5']) == '5'
Run this code and the tests in the Groovy console to verify that it works
The code I am using with Jenkins ExtendedChoiceParameter (tolerant to non-integer fragments in the version string)
def vers = ['none']
new File(this.getBinding().getVariable('dir')).eachDir() { dir -> dirs.add(dir.getName()) }
vers.sort{x, y ->
def xa = x.tokenize('._-'); def ya = y.tokenize('._-')
def sz = Math.min(xa.size(), ya.size())
for (int i = 0; i < sz; ++i) {
def xs = xa[i]; def ys = ya[i];
if (xs.isInteger() && ys.isInteger()) {
def xn = xs.toInteger()
def yn = ys.toInteger()
if (xn != yn) { return xn <=> yn }
} else if (xs != ys) {
return xs <=> ys
}
}
return xa.size() <=> ya.size()
}.reverse().join(',')
Here my solution:
def availVersion = "1.5.0.2"
def ownVersion = "2.6.0.1"
def availTokens = availVersion.split('\\.')
def ownTokens = ownVersion.split('\\.')
def availSize = availTokens.size()
def ownSize = ownTokens.size()
def maxSize = Math.max(availSize, ownSize)
for (int i = 1; i <= maxSize; i++) {
def availItem = ((i <= availSize) ? availTokens[i - 1] : 0)
def ownItem = ((i <= ownSize) ? ownTokens[i - 1] : 0)
print "Avail: ${availItem} -> Own: ${ownItem}\n"
if ((ownItem > availItem) || ( (i == maxSize) && (ownItem >= availItem) )) {
print "Upgrade NOT needed.\n"
return
}
}
print "Upgrade needed!\n"