I am trying to edit a current XSLT. The functionality I want is when the value of \"//code_no\" ends with 01 I want to edit the current city location. Currently this functio
XSLT 1.0 uses XPath 1.0, which does not include any function named ends-with
. You can fake it using the technique found here:
Not exactly ends with, but nicer look than the substring-solution and still suitable for certain situations:
<xsl:template match="*[contains(name(), 'substr')]"/>
The XPath 1.0 equivalent of (the XPath 2.0) expression:
ends-with($s, $t)
is:
$t = substring($s, string-length($s) - string-length($t) +1)
You need just to substitute $s
and $t
in the last XPath expression with, respectively, the string to be tested, and the ending to be tested.
Here is a complete example:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="x|y">
<xsl:value-of select="name()"/> ends-with '_01': <xsl:value-of select=
"'_01' = substring(., string-length() - 2)"/>
=============
</xsl:template>
</xsl:stylesheet>
when this transformation is applied on the following XML document (none was provided in the question!!!):
<t>
<x>abcd_01</x>
<y>abcd_11</y>
</t>
the wanted, correct result is produced:
x ends-with '_01': true
=============
y ends-with '_01': false
=============
I used
contains($string, $part) and normalize-space(substring-after($string, $part)) = ''
Where
we are checking if $string ends with $part
In special cases, if you know that some character can not be contained in tag for example § you can do this:
<xsl:if test="contains(concat(code_no,'§'),'01§')">
<td align="left" width="33%"><SPAN style="font-size: 12pt; font-family: Arial;">
<a> <b><u><xsl:value-of select="//city"/>, <xsl:value-of select="//state"/>
</u></b></a></SPAN></td>
</xsl:if>