reading two integers in one line using C#

Question

i know how to make a console read two integers but each integer by it self like this

int a = int.Parse(Console.ReadLine());
int b = int.Parse(Console.ReadLin         


        

Answer 1

int a, b;
string line = Console.ReadLine();
string[] numbers= line.Split(' ');
a = int.Parse(numbers[0]);
b = int.Parse(numbers[1]);

Answer 2

You need something like (no error-checking code)

var ints = Console
            .ReadLine()
            .Split()
            .Select(int.Parse);

This reads a line, splits on whitespace and parses the split strings as integers. Of course in reality you would want to check if the entered strings are in fact valid integers (int.TryParse).

Answer 3

Read the line into a string, split the string, and then parse the elements. A simple version (which needs to have error checking added to it) would be:

string s = Console.ReadLine();
string[] values = s.Split(' ');
int a = int.Parse(values[0]);
int b = int.Parse(values[1]);

Answer 4

in 1 line, thanks to LinQ and regular expression (no type-checking neeeded)

var numbers = from Match number in new Regex(@"\d+").Matches(Console.ReadLine())
                    select int.Parse(number.Value);

Answer 5

Then you should first store it in a string and then split it using the space as token.

Answer 6

public static class ConsoleInput
{
    public static IEnumerable<int> ReadInts()
    {
        return SplitInput(Console.ReadLine()).Select(int.Parse);
    }

    private static IEnumerable<string> SplitInput(string input)
    {
        return Regex.Split(input, @"\s+")
                    .Where(x => !string.IsNullOrWhiteSpace(x));
    }
}