Regex to match 2 digits, optional decimal, two digits

Question

I\'ve spent half an hour trying to get this, maybe someone can come up with it quickly.

I need a regular expression that will match one or two digits, followed by an

Answer 1

  \d{1,}(\.\d{1,2})|\d{0,9}

tested in https://regexr.com/

matches with numbers with 2 decimals or just one, or numbers without decimals.

You can change the number or decimals you want by changing the number 2

Answer 2

(?<![\d.])(\d{1,2}|\d{0,2}\.\d{1,2})?(?![\d.])

Matches:

• Your examples
• 33.

Does not match:

• 333.33
• 33.333

Answer 3

You mentioned that you want the regex to match each of those strings, yet you previously mention that the is 1-2 digits before the decimal?

This will match 1-2 digits followed by a possible decimal, followed by another 1-2 digits but FAIL on your example of .33

\d{1,2}\.?\d{1,2}

This will match 0-2 digits followed by a possible deciaml, followed by another 1-2 digits and match on your example of .33

\d{0,2}\.?\d{1,2}

Not sure exactly which one you're looking for.

Answer 4

To build on Lee's answer, you need to anchor the expression to satisfy the requirement of not having more than 2 numbers before the decimal.

If each number is a separate string, you can use the string anchors:

^\d{0,2}(\.\d{1,2})?$

If each number is within a string, you can use the word anchors:

\b\d{0,2}(\.\d{1,2})?\b

Answer 5

^\d{0,2}\.?\d{1,2}$

Answer 6

^(\d{0,2}\\.)?\d{1,2}$

\d{1,2}$ matches a 1-2 digit number with nothing after it (3, 33, etc.), (\d{0,2}\.)? matches optionally a number 0-2 digits long followed by a period (3., 44., ., etc.). Put them together and you've got your regex.