I found the following way hex to binary conversion:
String binAddr = Integer.toBinaryString(Integer.parseInt(hexAddr, 16));
While this app
import java.util.*;
public class HexadeciamlToBinary
{
public static void main()
{
Scanner sc=new Scanner(System.in);
System.out.println("enter the hexadecimal number");
String s=sc.nextLine();
String p="";
long n=0;
int c=0;
for(int i=s.length()-1;i>=0;i--)
{
if(s.charAt(i)=='A')
{
n=n+(long)(Math.pow(16,c)*10);
c++;
}
else if(s.charAt(i)=='B')
{
n=n+(long)(Math.pow(16,c)*11);
c++;
}
else if(s.charAt(i)=='C')
{
n=n+(long)(Math.pow(16,c)*12);
c++;
}
else if(s.charAt(i)=='D')
{
n=n+(long)(Math.pow(16,c)*13);
c++;
}
else if(s.charAt(i)=='E')
{
n=n+(long)(Math.pow(16,c)*14);
c++;
}
else if(s.charAt(i)=='F')
{
n=n+(long)(Math.pow(16,c)*15);
c++;
}
else
{
n=n+(long)Math.pow(16,c)*(long)s.charAt(i);
c++;
}
}
String s1="",k="";
if(n>1)
{
while(n>0)
{
if(n%2==0)
{
k=k+"0";
n=n/2;
}
else
{
k=k+"1";
n=n/2;
}
}
for(int i=0;i<k.length();i++)
{
s1=k.charAt(i)+s1;
}
System.out.println("The respective binary number is : "+s1);
}
else
{
System.out.println("The respective binary number is : "+n);
}
}
}