Regex that matches a newline (\n) in C#

Question

OK, this one is driving me nuts.... I have a string that is formed thus:

var newContent = string.Format(\"({0})\\n{1}\", stripped_content, reply)


        

Answer 1

Counter-intuitive as it is, you could use both Multiline and Singleline option.

Regex.Match(input, @"(.+)^(.*)", RegexOptions.Multiline | RegexOptions.Singleline)

First capturing group will contain first line (including \r and \n) and second group will have second line.

Why:

• Multiline:

  ^ and $ match the beginning and end of each line (instead of the beginning and end of the input string).

• Singleline:

  The period (.) matches every character (instead of every character except \n)

  see docs

Answer 2

Actually it works but with opposite option i.e.

 RegexOptions.Singleline

Answer 3

You are probably going to have a \r before your \n. Try replacing the \s with (\r\n).

Answer 4

If you're trying to match line endings then you may find

Regex.Match("string", "regex", RegexOptions.Multiline)

helps

Answer 5

Think I may be a bit late to the party, but still hope this helps.

I needed to get multiple tokens between two hash signs.

Example i/p:

## token1 ##
## token2 ##
## token3_a
token3_b
token3_c ##

This seemed to work in my case:

var matches = Regex.Matches (mytext, "##(.*?)##", RegexOptions.Singleline);

Of course, you may want to replace the double hash signs at both ends with your own chars.

HTH.

Answer 6

If you specify RegexOptions.Multiline then you can use ^ and $ to match the start and end of a line, respectively.

If you don't wish to use this option, remember that a new line may be any one of the following: \n, \r, \r\n, so instead of looking only for \n, you should perhaps use something like: [\n\r]+, or more exactly: (\n|\r|\r\n).