Why does libc++'s implementation of std::string take up 3x memory as libstdc++?

Question

Consider the following test program:

#include 
#include 
#include 

int main()
{
    std::cout << sizeof(st         


        

Answer 1

Summary: It only looks like libstdc++ uses one char*. In fact, it allocates more memory.

So, you should not be concerned that Clang's libc++ implementation is memory inefficient.

From the documentation of libstdc++ (under Detailed Description):

A string looks like this:

                                        [_Rep]
                                        _M_length
   [basic_string<char_type>]            _M_capacity
   _M_dataplus                          _M_refcount
   _M_p ---------------->               unnamed array of char_type

Where the _M_p points to the first character in the string, and you cast it to a pointer-to-_Rep and subtract 1 to get a pointer to the header.

This approach has the enormous advantage that a string object requires only one allocation. All the ugliness is confined within a single pair of inline functions, which each compile to a single add instruction: _Rep::_M_data(), and string::_M_rep(); and the allocation function which gets a block of raw bytes and with room enough and constructs a _Rep object at the front.

The reason you want _M_data pointing to the character array and not the _Rep is so that the debugger can see the string contents. (Probably we should add a non-inline member to get the _Rep for the debugger to use, so users can check the actual string length.)

So, it just looks like one char* but that is misleading in terms of memory usage.

Previously libstdc++ basically used this layout:

  struct _Rep_base
  {
    size_type               _M_length;
    size_type               _M_capacity;
    _Atomic_word            _M_refcount;
  };

That is closer to the results from libc++.

libc++ uses "short string optimization". The exact layout depends on whether _LIBCPP_ABI_ALTERNATE_STRING_LAYOUT is defined. If it is defined, the data pointer will be word-aligned if the string is short. For details, see the source code.

Short string optimization avoids heap allocations, so it also looks more costly than libstdc++ implementation if you only consider the parts that are allocated on the stack. sizeof(std::string) only shows the stack usage not the overall memory usage (stack + heap).

Answer 2

You should not be concerned, standard library implementors know what they are doing.

Using the latest code from the GCC subversion trunk libstdc++ gives these numbers:

32 320 344

This is because as of a few weeks ago I switched the default std::string implementation to use the small-string optimisation (with space for 15 chars) instead of the copy-on-write implementation that you tested with.

Answer 3

Here is a short program to help you explore both kinds of memory usage of std::string: stack and heap.

#include <string>
#include <new>
#include <cstdio>
#include <cstdlib>

std::size_t allocated = 0;

void* operator new (size_t sz)
{
    void* p = std::malloc(sz);
    allocated += sz;
    return p;
}

void operator delete(void* p) noexcept
{
    return std::free(p);
}

int
main()
{
    allocated = 0;
    std::string s("hi");
    std::printf("stack space = %zu, heap space = %zu, capacity = %zu\n",
     sizeof(s), allocated, s.capacity());
}

Using http://melpon.org/wandbox/ it is easy to get output for different compiler/lib combinations, for example:

gcc 4.9.1:

stack space = 8, heap space = 27, capacity = 2

gcc 5.0.0:

stack space = 32, heap space = 0, capacity = 15

clang/libc++:

stack space = 24, heap space = 0, capacity = 22

VS-2015:

stack space = 32, heap space = 0, capacity = 15

(the last line is from http://webcompiler.cloudapp.net)

The above output also shows capacity, which is a measure of how many chars the string can hold before it has to allocate a new, larger buffer from the heap. For the gcc-5.0, libc++, and VS-2015 implementations, this is a measure of the short string buffer. That is, the size buffer allocated on the stack to hold short strings, thus avoiding the more expensive heap allocation.

It appears that the libc++ implementation has the smallest (stack usage) of the short-string implementations, and yet contains the largest of the short string buffers. And if you count total memory usage (stack + heap), libc++ has the smallest total memory usage for this 2-character string among all 4 of these implementations.

It should be noted that all of these measurements were taken on 64 bit platforms. On 32 bit, the libc++ stack usage will go down to 12, and the small string buffer goes down to 10. I don't know the behavior of the other implementations on 32 bit platforms, but you can use the above code to find out.

Answer 4

I haven't checked the actual implementations in source code, but I remember checking this when I was working on my C++ string library. A 24 byte string implementation is typical. If the length of the string is smaller than or equal to 16 bytes, instead of malloc'ing from the heap, it copies the string into the internal buffer of size 16 bytes. Otherwise, it mallocs and stores the memory address etc. This minor buffering actually helps in terms of running time performance.

For some compilers, there's an option to turn the internal buffer off.