I am new to Scrapy and I am working on a scraping exercise and I am using the CrawlSpider. Although the Scrapy framework works beautifully and it follows the relevant links,
There's a number of ways of doing this, but one of the simplest is to implement parse_start_url
and then modify start_urls
from scrapy.contrib.spiders import CrawlSpider, Rule
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor
from scrapy.selector import HtmlXPathSelector
class DownloadSpider(CrawlSpider):
name = 'downloader'
allowed_domains = ['bnt-chemicals.de']
start_urls = ["http://www.bnt-chemicals.de/tunnel/index.htm"]
rules = (
Rule(SgmlLinkExtractor(allow='prod'), callback='parse_item', follow=True),
)
fname = 1
def parse_start_url(self, response):
return self.parse_item(response)
def parse_item(self, response):
open(str(self.fname)+ '.txt', 'a').write(response.url)
open(str(self.fname)+ '.txt', 'a').write(','+ str(response.meta['depth']))
open(str(self.fname)+ '.txt', 'a').write('\n')
open(str(self.fname)+ '.txt', 'a').write(response.body)
open(str(self.fname)+ '.txt', 'a').write('\n')
self.fname = self.fname + 1
Just change your callback to parse_start_url
and override it:
from scrapy.contrib.spiders import CrawlSpider, Rule
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor
class DownloadSpider(CrawlSpider):
name = 'downloader'
allowed_domains = ['bnt-chemicals.de']
start_urls = [
"http://www.bnt-chemicals.de",
]
rules = (
Rule(SgmlLinkExtractor(allow='prod'), callback='parse_start_url', follow=True),
)
fname = 0
def parse_start_url(self, response):
self.fname += 1
fname = '%s.txt' % self.fname
with open(fname, 'w') as f:
f.write('%s, %s\n' % (response.url, response.meta.get('depth', 0)))
f.write('%s\n' % response.body)