Running Bash commands in Java

Question

I have the following class. It allows me to execute commands through java.

public class ExecuteShellCommand {

public String executeCommand(String command) {         


        

Answer 1

You could use the bash command "pmset -g batt" like in the method bellow witch returns the battery percentage

public int getPercentage() {
    Process process = null;
    try {
        process = Runtime.getRuntime().exec("pmset -g batt");
    } catch (IOException e) {
        e.printStackTrace();
    }
    BufferedReader reader = new BufferedReader(new InputStreamReader(
            process.getInputStream()));
    String s = null;
    String y = "";
    while (true) {
        try {
            if (!((s = reader.readLine()) != null)) break;
        } catch (IOException e) {
            e.printStackTrace();
        }
        y += s;
        System.out.println("Script output: " + s);
    }
    return Integer.parseInt(y.substring(y.indexOf(')') + 2, y.indexOf('%')));
}

Answer 2

You start a new process with Runtime.exec(command). Each process has a working directory. This is normally the directory in which the parent process was started, but you can change the directory in which your process is started.

I would recommend to use ProcessBuilder

ProcessBuilder pb = new ProcessBuilder("ls");
pb.inheritIO();
pb.directory(new File("bin"));
pb.start();

If you want to run multiple commands in a shell it would be better to create a temporary shell script and run this.

public void executeCommands() throws IOException {

    File tempScript = createTempScript();

    try {
        ProcessBuilder pb = new ProcessBuilder("bash", tempScript.toString());
        pb.inheritIO();
        Process process = pb.start();
        process.waitFor();
    } finally {
        tempScript.delete();
    }
}

public File createTempScript() throws IOException {
    File tempScript = File.createTempFile("script", null);

    Writer streamWriter = new OutputStreamWriter(new FileOutputStream(
            tempScript));
    PrintWriter printWriter = new PrintWriter(streamWriter);

    printWriter.println("#!/bin/bash");
    printWriter.println("cd bin");
    printWriter.println("ls");

    printWriter.close();

    return tempScript;
}

Of course you can also use any other script on your system. Generating a script at runtime makes sometimes sense, e.g. if the commands that are executed have to change. But you should first try to create one script that you can call with arguments instead of generating it dynamically at runtime.

It might also be reasonable to use a template engine like velocity if the script generation is complex.

EDIT

You should also consider to hide the complexity of the process builder behind a simple interface.

Separate what you need (the interface) from how it is done (the implementation).

public interface FileUtils {
    public String[] listFiles(String dirpath);
}

You can then provide implementations that use the process builder or maybe native methods to do the job and you can provide different implementations for different environments like linux or windows.

Finally such an interface is also easier to mock in unit tests.

Answer 3

You can form one complex bash command that does everything: "ls; cd bin; ls". To make this work you need to explicitly invoke bash. This approach should give you all the power of the bash command line (quote handling, $ expansion, pipes, etc.).

/**
 * Execute a bash command. We can handle complex bash commands including
 * multiple executions (; | && ||), quotes, expansions ($), escapes (\), e.g.:
 *     "cd /abc/def; mv ghi 'older ghi '$(whoami)"
 * @param command
 * @return true if bash got started, but your command may have failed.
 */
public static boolean executeBashCommand(String command) {
    boolean success = false;
    System.out.println("Executing BASH command:\n   " + command);
    Runtime r = Runtime.getRuntime();
    // Use bash -c so we can handle things like multi commands separated by ; and
    // things like quotes, $, |, and \. My tests show that command comes as
    // one argument to bash, so we do not need to quote it to make it one thing.
    // Also, exec may object if it does not have an executable file as the first thing,
    // so having bash here makes it happy provided bash is installed and in path.
    String[] commands = {"bash", "-c", command};
    try {
        Process p = r.exec(commands);

        p.waitFor();
        BufferedReader b = new BufferedReader(new InputStreamReader(p.getInputStream()));
        String line = "";

        while ((line = b.readLine()) != null) {
            System.out.println(line);
        }

        b.close();
        success = true;
    } catch (Exception e) {
        System.err.println("Failed to execute bash with command: " + command);
        e.printStackTrace();
    }
    return success;
}

Answer 4

for future reference: running bash commands after cd , in a subdirectory:

import java.io.BufferedReader;
import java.io.InputStreamReader;

/*

$ ( D=somewhere/else ; mkdir -p $D ; cd $D ; touch file1 file2 ; )
$ javac BashCdTest.java && java BashCdTest
 .. stdout: -rw-r--r-- 1 ubuntu ubuntu 0 Dec 28 12:47 file1
 .. stdout: -rw-r--r-- 1 ubuntu ubuntu 0 Dec 28 12:47 file2
 .. stderr: /bin/ls: cannot access isnt_there: No such file or directory
 .. exit code:2

*/
class BashCdTest
    {
    static void execCommand(String[] commandArr)
        {
        String line;
        try
            {
            Process p = Runtime.getRuntime().exec(commandArr);
            BufferedReader stdoutReader = new BufferedReader(new InputStreamReader(p.getInputStream()));
            while ((line = stdoutReader.readLine()) != null) {
                // process procs standard output here
                System.out.println(" .. stdout: "+line);
                }
            BufferedReader stderrReader = new BufferedReader(new InputStreamReader(p.getErrorStream()));
            while ((line = stderrReader.readLine()) != null) {
                // process procs standard error here
                System.err.println(" .. stderr: "+line);
                }
            int retValue = p.waitFor();
            System.out.println(" .. exit code:"+Integer.toString(retValue));
            }
        catch(Exception e)
            { System.err.println(e.toString()); }
        }

    public static void main(String[] args)
        {
        String flist = "file1 file2 isnt_there";
        String outputDir = "./somewhere/else";
        String[] cmd = {
            "/bin/bash", "-c",
            "cd "+outputDir+" && /bin/ls -l "+flist+" && /bin/rm "+flist
            };
        execCommand(cmd);
        }
    }

Answer 5

Each command is executed individually. They dont share the context.

Answer 6

each command you are running has its own bash shell, so once you cd to that directory and for next command you are opening new bash shell

try changing your command to

ls bin