Using a list as a data source for DataGridView

Question

I\'ve extracted the setting names and their respective values out of a configuration file into an ordered dictionary. The dictionary contains keys and values which are of th

Answer 1

Set the DataGridView property

    gridView1.AutoGenerateColumns = true;

And make sure the list of objects your are binding, those object properties should be public.

Answer 2

this Func may help you . it add every list object to grid view

private void show_data()
        {
            BindingSource Source = new BindingSource();

            for (int i = 0; i < CC.Contects.Count; i++)
            {
                Source.Add(CC.Contects.ElementAt(i));
            };


            Data_View.DataSource = Source;

        }

I write this for simple database app

Answer 3

First, I don't understand why you are adding all the keys and values count times, Index is never used.

I tried this example :

        var source = new BindingSource();
        List<MyStruct> list = new List<MyStruct> { new MyStruct("fff", "b"),  new MyStruct("c","d") };
        source.DataSource = list;
        grid.DataSource = source;

and that work pretty well, I get two columns with the correct names. MyStruct type exposes properties that the binding mechanism can use.

    class MyStruct
   {
    public string Name { get; set; }
    public string Adres { get; set; }


    public MyStruct(string name, string adress)
    {
        Name = name;
        Adres = adress;
    }
  }

Try to build a type that takes one key and value, and add it one by one. Hope this helps.