How to check if a string is numeric? [duplicate]

Answer 1

You can also use ApacheCommons StringUtils.isNumeric - http://commons.apache.org/proper/commons-lang/javadocs/api-2.6/org/apache/commons/lang/StringUtils.html#isNumeric(java.lang.String)

Answer 2

Use below method,

public static boolean isNumeric(String str)  
{  
  try  
  {  
    double d = Double.parseDouble(str);  
  }  
  catch(NumberFormatException nfe)  
  {  
    return false;  
  }  
  return true;  
}

If you want to use regular expression you can use as below,

public static boolean isNumeric(String str)
{
  return str.matches("-?\\d+(\\.\\d+)?");  //match a number with optional '-' and decimal.
}

Answer 3

public static boolean isNumeric(String string) {
    if (string == null || string.isEmpty()) {
        return false;
    }
    int i = 0;
    int stringLength = string.length();
    if (string.charAt(0) == '-') {
        if (stringLength > 1) {
            i++;
        } else {
            return false;
        }
    }
    if (!Character.isDigit(string.charAt(i))
            || !Character.isDigit(string.charAt(stringLength - 1))) {
        return false;
    }
    i++;
    stringLength--;
    if (i >= stringLength) {
        return true;
    }
    for (; i < stringLength; i++) {
        if (!Character.isDigit(string.charAt(i))
                && string.charAt(i) != '.') {
            return false;
        }
    }
    return true;
}

Answer 4

I wrote this little method lastly in my program so I can check if a string is numeric or at least every single char is a number.

private boolean isNumber(String text){
    if(text != null || !text.equals("")) {
        char[] characters = text.toCharArray();
        for (int i = 0; i < text.length(); i++) {
            if (characters[i] < 48 || characters[i] > 57)
                return false;
        }
    }
    return true;
}

Answer 5

Here's how to check if the input contains a digit:

if (input.matches(".*\\d.*")) {
    // there's a digit somewhere in the input string 
}

Answer 6

Many options explored at http://www.coderanch.com/t/405258/java/java/String-IsNumeric

One more is

public boolean isNumeric(String s) {  
    return s != null && s.matches("[-+]?\\d*\\.?\\d+");  
}  

Might be overkill but Apache Commons NumberUtils seems to have some helpers as well.