Sorting a Django QuerySet by a property (not a field) of the Model

Question

Some code and my goal

My (simplified) model:

class Stop(models.Model):
    EXPRESS_STOP = 0
    LOCAL_STOP   = 1

    STOP_TYPES = (
        (EXPRE         


        

Answer 1

Use QuerySet.extra() along with CASE ... END to define a new field, and sort on that.

Stops.objects.extra(select={'cost': 'CASE WHEN price=0 THEN 0 '
  'WHEN type=:EXPRESS_STOP THEN price/2 WHEN type=:LOCAL_STOP THEN price*2'},
  order_by=['cost'])

That, or cast the QuerySet returned from the rest to a list, then use L.sort(key=operator.attrgetter('cost')) on it.