How to copy HashMap (not shallow copy) in Java

后端 未结 5 860
情书的邮戳
情书的邮戳 2020-11-30 04:32

I need to make a copy of HashMap > but when I change something in the copy I want the original to stay the same. i.e w

相关标签:
5条回答
  • 2020-11-30 04:55

    You can try deep cloning. Have a look for example at https://code.google.com/p/cloning/

    0 讨论(0)
  • 2020-11-30 04:57

    You are making a copy of the HashMap itself, so changing the HashMap copy will not change the original HashMap (i.e. adding or removing entries), but because the objects you have stored are not primitive types, the List that you retrieve with a given key will be the same whether retrieved from the first or the second Map.

    Thus, there is still only ONE copy of that list, referenced by both maps: changing the List changes it no matter which reference you use to access it.

    If you want the actual List to be a separate copy, you will have to do as you said: iterate over the entry set of the HashMap and create a copy of each List manually, adding it to the new map as you go.

    If there is a better way than that, I don't know what it is.

    0 讨论(0)
  • 2020-11-30 05:02

    This does need iteration unfortunately. But it's pretty trivial with Java 8 streams:

    mapCopy = map.entrySet().stream()
        .collect(Collectors.toMap(e -> e.getKey(), e -> List.copyOf(e.getValue())))
    
    0 讨论(0)
  • 2020-11-30 05:02

    Serialize to json and deserialize afterwards:

    Map<String, Object> originalMap = new HashMap<>();
    String json = new Gson().toJson(originalMap);
    Map<String, Object> mapCopy = new Gson().fromJson(
        json, new TypeToken<Map<String, Object>>() {}.getType());
    

    For special classes you might need to write a custom deserializer.

    0 讨论(0)
  • 2020-11-30 05:03

    You're right that a shallow copy won't meet your requirements. It will have copies of the Lists from your original map, but those Lists will refer to the same List objects, so that a modification to a List from one HashMap will appear in the corresponding List from the other HashMap.

    There is no deep copying supplied for a HashMap in Java, so you will still have to loop through all of the entries and put them in the new HashMap. But you should also make a copy of the List each time also. Something like this:

    public static HashMap<Integer, List<MySpecialClass>> copy(
        HashMap<Integer, List<MySpecialClass>> original)
    {
        HashMap<Integer, List<MySpecialClass>> copy = new HashMap<Integer, List<MySpecialClass>>();
        for (Map.Entry<Integer, List<MySpecialClass>> entry : original.entrySet())
        {
            copy.put(entry.getKey(),
               // Or whatever List implementation you'd like here.
               new ArrayList<MySpecialClass>(entry.getValue()));
        }
        return copy;
    }
    

    If you want to modify your individual MySpecialClass objects, and have the changes not be reflected in the Lists of your copied HashMap, then you will need to make new copies of them too.

    0 讨论(0)
提交回复
热议问题