How to test if a point is inside of a convex polygon in 2D integer coordinates?

Question

The polygon is given as a list of Vector2I objects (2 dimensional, integer coordinates). How can i test if a given point is inside? All implementations i found on the web fa

Answer 1

Or from the man that wrote the book see - geometry page

Specifically this page, he discusses why winding rule is generally better than ray crossing.

edit - Sorry this isn't Jospeh O'Rourke who wrote the excellent book Computational Geometry in C, it's Paul Bourke but still a very very good source of geometry algorithms.

Answer 2

If the polygon is convex, then in C#, the following implements the "test if always on same side" method, and runs at most at O(n of polygon points):

public static bool IsInConvexPolygon(Point testPoint, List<Point> polygon)
{
    //Check if a triangle or higher n-gon
    Debug.Assert(polygon.Length >= 3);

    //n>2 Keep track of cross product sign changes
    var pos = 0;
    var neg = 0;

    for (var i = 0; i < polygon.Count; i++)
    {
        //If point is in the polygon
        if (polygon[i] == testPoint)
            return true;

        //Form a segment between the i'th point
        var x1 = polygon[i].X;
        var y1 = polygon[i].Y;

        //And the i+1'th, or if i is the last, with the first point
        var i2 = i < polygon.Count - 1 ? i + 1 : 0;

        var x2 = polygon[i2].X;
        var y2 = polygon[i2].Y;

        var x = testPoint.X;
        var y = testPoint.Y;

        //Compute the cross product
        var d = (x - x1)*(y2 - y1) - (y - y1)*(x2 - x1);

        if (d > 0) pos++;
        if (d < 0) neg++;

        //If the sign changes, then point is outside
        if (pos > 0 && neg > 0)
            return false;
    }

    //If no change in direction, then on same side of all segments, and thus inside
    return true;
}