Convert short to byte[] in Java

Question

How can I convert a short (2 bytes) to a byte array in Java, e.g.

short x = 233;
byte[] ret = new byte[2];

...

it should be s

Answer 1

public short bytesToShort(byte[] bytes) {
     return ByteBuffer.wrap(bytes).order(ByteOrder.LITTLE_ENDIAN).getShort();
}

public byte[] shortToBytes(short value) {
    byte[] returnByteArray = new byte[2];
    returnByteArray[0] = (byte) (value & 0xff);
    returnByteArray[1] = (byte) ((value >>> 8) & 0xff);
    return returnByteArray;
}

Answer 2

A cleaner, albeit far less efficient solution is:

ByteBuffer buffer = ByteBuffer.allocate(2);
buffer.putShort(value);
return buffer.array();

Keep this in mind when you have to do more complex byte transformations in the future. ByteBuffers are very powerful.

Answer 3

ret[0] = (byte)(x & 0xff);
ret[1] = (byte)((x >> 8) & 0xff);

Answer 4

Short to bytes convert method In Kotlin works for me:

 fun toBytes(s: Short): ByteArray {
    return byteArrayOf((s.toInt() and 0x00FF).toByte(), ((s.toInt() and 0xFF00) shr (8)).toByte())
}

Answer 5

Figured it out, its:

public static byte[] toBytes(short s) {
    return new byte[]{(byte)(s & 0x00FF),(byte)((s & 0xFF00)>>8)};
}

Answer 6

short to byte

short x=17000;    
byte res[]=new byte[2];    
res[i]= (byte)(((short)(x>>7)) & ((short)0x7f) | 0x80 );    
res[i+1]= (byte)((x & ((short)0x7f)));

byte to short

short x=(short)(128*((byte)(res[i] &(byte)0x7f))+res[i+1]);