Can I use a regular expression in querySelectorAll?

Question

On a page I\'m doing I will be ending up with custom link elements like this:

Answer 1

I know this is 7 years old, but this is how you do it (for attribute values):

function DOMRegex(regex) {
    let output = [];
    for (let i of document.querySelectorAll('*')) {
        if (regex.test(i.type)) { // or whatever attribute you want to search
            output.push(i);
        }
    }
    return output;
}
console.log(DOMRegex(/^service\//)); // your regex here

<link rel="multiply" type="service/math" src="path/to/service">
<link rel="substract" type="service/math" src="path/to/service">
<link rel="test" type="notservice/math" src="path/to/notservice">
<div id="some-other-node"></div>

To search all element attributes, you can use this:

function DOMRegex(regex) {
    let output = [];
    for (let i of document.querySelectorAll('*')) {
        for (let j of i.attributes) {
            if (regex.test(j.value)) {
                output.push({
                    'element': i,
                    'attribute name': j.name,
                    'attribute value': j.value
                });
            }
        }
    }
    return output;
}
console.log(DOMRegex(/(?<!t)service/)); // your regex here

<link rel="multiply" type="service/math" src="path/to/service">
<link rel="substract" type="service/math" src="path/to/service">
<link rel="test" type="notservice/math" src="path/to/notservice">
<div id="some-other-node"></div>

I put it in a nice object layout for you.

Answer 2

You can't really use a regular expression in a selector but CSS selectors are powerful enough for your need with a "starts with" syntax inspired by regexes.

You can use a substring matching attribute selectors : link[type^=service]

Reads "Nodes of type link with an attribute type starting with "service"

From the formal specification:

[att^=val]

Represents an element with the att attribute whose value begins with the prefix "val". If "val" is the empty string then the selector does not represent anything.

Working JSFiddle