How Threadpool re-use Threads and how it works

Question

My multithreading concepts are weak and trying to learn.

In Java what I know is, we can\'t call a thread more than once:

Thread t = new Thread; //So         


        

Answer 1

The process workes in two parts:

Submission of task: Thread pools are tightly coupled with a blocking Queue. When we say executor.execute(runnable). The runnable/callable is enqued in the queue.

Execution of tasks: Now the tasks need to be picked up from the queue. Lets say whenever a task is submitted in the queue, it must be picked up and executed.

So there are threads which will be running infinite loop and watching the queue for tasks. As soon as the tasks are available one thread will pick it and execute.

Answer 2

In Thread Pool Instead of creating new threads when new tasks arrive, a thread pool keeps a number of idle threads that are ready for executing tasks as needed. After a thread completes execution of a task, it does not die. Instead it remains idle in the pool waiting to be chosen for executing new tasks.

You can limit a definite number of concurrent threads in the pool, which is useful to prevent overload. If all threads are busily executing tasks, new tasks are placed in a queue, waiting for a thread becomes available

Answer 3

If there is no need to create new Thread in ThreadPool scenario, then how it works with same thread which just finished its run method, will that Thread can be used again?

Simple - the original thread never actually completes. It just waits for another task to execute. In pseudo-code:

// No, this isn't even slightly accurate! General impression only :)
while (!pool.isShutdown()) {
    Runnable task = pool.waitForTaskOnQueue();
    task.run();
}

(Obviously when a thread pool is shut down, it would need to stop waiting threads from waiting for another task, too - but hopefully you get the general idea.)

Answer 4

So, considering above 3 steps, With Threadpool step 1 and Step 3 can be eliminated after fixed number of Thread Creation. only Step 2 for each task will be executed that is why Threadpool is faster? can we say like this? am I correct?

Yes you are correct. Thread creation and destruction is one of the costly task. As in a thread pool threads are already created so the overhead of thread creation is not there. But if you have much more higher threads than it should have, it will be pretty bad for your application. It may go OutofMemorry or may be into some other issues. So to fix a thread pool size use the below formula:

no of threads = 2 * no_of_cores * no_of_disks * percentage CPU utilization you need * (1 + (W/ C))

(W/C) is the fraction stating Wait time to Compute time.