Android- how can I convert android.net.Uri object to java.net.URI object?

前端 未结 5 1430
一整个雨季
一整个雨季 2020-11-30 02:41

I am trying to get a FileInputStream object on an image that the user selects from the picture gallery. This is the android URI returned by a

相关标签:
5条回答
  • 2020-11-30 03:15

    Found the correct way to open InputStream from content URI:

    InputStream fileInputStream=yourContext.getContentResolver().openInputStream(uri);
    

    That's all!

    0 讨论(0)
  • 2020-11-30 03:24

    I voted for jgilrincon's answer. I can't comment due to low reputation, and here goes some additional info - you can use FileHelper.java from Apache Cordova project, it has functions that you need for file handling from Uri strings, considering mediastore as well (and app assets folder)

    Particularly this method provides InputStream from Uri:

    public static InputStream getInputStreamFromUriString(String uriString, Activity cordova)
    
    0 讨论(0)
  • 2020-11-30 03:28

    There is a solution to your original question (convert Uri to URI):

    1. Get the real file path (look this code: Get filename and path from URI from mediastore)

    2. Get the URI using the real path and the constructor: URI(String uri)

    If you need more details, look here:

    How to delete a video recorded using an Intent with ACTION_VIDEO_CAPTURE?

    0 讨论(0)
  • 2020-11-30 03:32

    Since the String constructing doesn't work have you tried just constructing it your self?

    android.net.URI auri = new android.net.URI(what ever);
    java.net.URI juri = new java.net.URI(auri.getSchema(),
                                         auri.getSchemaSpecificPart(),
                                         auri.getFragment());
    

    You might also want to double check that your getting valid data out of Android URI class. The docs as listed in my other answer discuss how it does pretty much no error checking. If there is infact an error the class just spits out garbage anyway and doesn't throw any exceptions. Which could very likely be why the java class which does do validation is throwing an exception.

    0 讨论(0)
  • 2020-11-30 03:35

    You could use the toString method of the android Uri in combination of the String based constructor of the Java URI.

    android.net.Uri auri = new android.net.Uri(what ever);
    java.net.URI juri = new java.net.URI(auri.toString());
    

    Android URI | Java URI

    0 讨论(0)
提交回复
热议问题