Suggestions to avoid bitmap Out of Memory error

Question

I am working on an android application. The application has a view containing lots of image. I had an error, I will try to give as much information as possible hoping someon

Answer 1

By Reducing/Scale size of the Image you can get rid out of the Out of Memory Exception, Try this

  BitmapFactory.Options options = new BitmapFactory.Options();
  options.inSampleSize = 6; 
  Bitmap receipt = BitmapFactory.decodeFile(photo.toString(),options);  //From File You can customise on your needs. 

Answer 2

just use this function to decode...this is perfect solution for your error..because i also getting same error and i got this solution..

public static Bitmap decodeFile(File f,int WIDTH,int HIGHT){
     try {
         //Decode image size
         BitmapFactory.Options o = new BitmapFactory.Options();
         o.inJustDecodeBounds = true;
         BitmapFactory.decodeStream(new FileInputStream(f),null,o);

         //The new size we want to scale to
         final int REQUIRED_WIDTH=WIDTH;
         final int REQUIRED_HIGHT=HIGHT;
         //Find the correct scale value. It should be the power of 2.
         int scale=1;
         while(o.outWidth/scale/2>=REQUIRED_WIDTH && o.outHeight/scale/2>=REQUIRED_HIGHT)
             scale*=2;

         //Decode with inSampleSize
         BitmapFactory.Options o2 = new BitmapFactory.Options();
         o2.inSampleSize=scale;
         return BitmapFactory.decodeStream(new FileInputStream(f), null, o2);
     } catch (FileNotFoundException e) {}
     return null;
 }

Answer 3

If u want to avoid OOM, u can catch OOM and increase the sampleSize until the image can be resolved:

private Bitmap getBitmapSafely(Resources res, int id, int sampleSize) {
// res = context.getResources(), id = R.drawable.yourimageid
    Bitmap bitmap = null;
    BitmapFactory.Options options = new BitmapFactory.Options();
    options.inPurgeable = true;
    options.inSampleSize = sampleSize;
    try {
          bitmap = BitmapFactory.decodeResource(res,
                      id, options);
    } catch (OutOfMemoryError oom) {
        Log.w("ImageView", "OOM with sampleSize " + sampleSize, oom);
        System.gc();
        bitmap = getBitmapSafely(res, id, sampleSize + 1);
    }

    return bitmap;
}

Hope it helps.

It is not suitable to catch the Error, just a workaround.

Answer 4

actually the problem is with the development os. In android unlike iOS , google people develop this based on camera resolution. Bitmaps take up a lot of memory, especially for rich images like photographs.Different cameras captures images with different pixels(different mobiles have different camera pixel capacity). Here in android based on that pixels only the captured image will take memory. so obviously a high resolution image will not uploaded by a phone with low pixel capacity. In android os allocates utmost 16MB to every application. If the uploaded image takes more than this then java.lang.OutofMemoryError: bitmap size exceeds VM budget will occur and application crashes. refer this http://developer.android.com/training/displaying-bitmaps/index.html

Answer 5

I wrote a summary of suggestions in another StackOverFlow question: Android: BitmapFactory.decodeStream() out of memory with a 400KB file with 2MB free heap

Answer 6

Hi you have to decode the file . for this try with the following method.

  public static Bitmap new_decode(File f) {

        // decode image size

        BitmapFactory.Options o = new BitmapFactory.Options();
        o.inJustDecodeBounds = true;
        o.inDither = false; // Disable Dithering mode

        o.inPurgeable = true; // Tell to gc that whether it needs free memory,
                                // the Bitmap can be cleared

        o.inInputShareable = true; // Which kind of reference will be used to
                                    // recover the Bitmap data after being
                                    // clear, when it will be used in the future
        try {
            BitmapFactory.decodeStream(new FileInputStream(f), null, o);
        } catch (FileNotFoundException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        }

        // Find the correct scale value. It should be the power of 2.
        final int REQUIRED_SIZE = 300;
        int width_tmp = o.outWidth, height_tmp = o.outHeight;
        int scale = 1;
        while (true) {
            if (width_tmp / 1.5 < REQUIRED_SIZE && height_tmp / 1.5 < REQUIRED_SIZE)
                break;
            width_tmp /= 1.5;
            height_tmp /= 1.5;
            scale *= 1.5;
        }

        // decode with inSampleSize
        BitmapFactory.Options o2 = new BitmapFactory.Options();
        // o2.inSampleSize=scale;
        o.inDither = false; // Disable Dithering mode

        o.inPurgeable = true; // Tell to gc that whether it needs free memory,
                                // the Bitmap can be cleared

        o.inInputShareable = true; // Which kind of reference will be used to
                                    // recover the Bitmap data after being
                                    // clear, when it will be used in the future
        // return BitmapFactory.decodeStream(new FileInputStream(f), null, o2);
        try {

//          return BitmapFactory.decodeStream(new FileInputStream(f), null,
//                  null);
            Bitmap bitmap= BitmapFactory.decodeStream(new FileInputStream(f), null, null);
            System.out.println(" IW " + width_tmp);
            System.out.println("IHH " + height_tmp);           
               int iW = width_tmp;
                int iH = height_tmp;

               return Bitmap.createScaledBitmap(bitmap, iW, iH, true);

        } catch (OutOfMemoryError e) {
            // TODO: handle exception
            e.printStackTrace();
            // clearCache();

            // System.out.println("bitmap creating success");
            System.gc();
            return null;
            // System.runFinalization();
            // Runtime.getRuntime().gc();
            // System.gc();
            // decodeFile(f);
        } catch (FileNotFoundException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
            return null;
        }

    }