MySQL PHP - SELECT WHERE id = array()? [duplicate]

Answer 1

Use IN.

$sql = 'SELECT * 
          FROM `table` 
         WHERE `id` IN (' . implode(',', array_map('intval', $array)) . ')';

Answer 2

What you are looking for is the IN() statement. This will test if a given field contains any of 1 or more values.

SELECT * FROM `Table` WHERE `id` IN (1, 2, 3)

You can use a simple loop to convert your $array variable into the proper format. Be sure to be mindful of SQL injection if your array values are coming from the front end.

Answer 3

Simply use the ID IN () syntax:

$sql = "SELECT FROM `table` WHERE `ID` IN (".implode(',',$array).")";

Answer 4

You can write your query like this:

select * from table where id in (1, 4, 6, 7)

You can add as many values as you need.

Answer 5

You'll want to use the IN operator:

$sql = 'SELECT FROM WHERE id IN (' . implode(",", $array) . ')';

There may be a limit in MySQL on how many values you can use in a list with the IN operator.

Answer 6

You can SELECT WHERE id IN (item1, item2...). Just loop through your PHP array to build your array for the query.