I need to load to R packages : tseries and chron
Both have a function named is.weekend
I always have in my environment the function from the second package I
You have probably already noticed that the order of loading the packages makes a difference, i.e. the package that gets loaded last will mask the functions in packages loaded earlier.
To specify the package that you want to use, the syntax is:
chron::is.weekend()
tseries::is.weekend()
In other words, use packagename::functionname()
In addition, if you know that you will always want to use the function in chron, you can define your own function as follows:
is.weekend <- chron::is.weekend #EDIT
i had 2 packages who had same function name ts() The 2 pacckages who had the same were :
?ts
Help on topic 'ts' was found in the following packages:
Time-Series Objects
(in package stats in library C:/Program Files/R/R-3.6.2/library)
Format time stamps
(in package bReeze in library C:/Users/mycomputer/Documents/R/win-library/3.6)
Solution : Then to use the function ts that comes with package forecast i used : because the help showed me that forcast was calling stats
Time-Series Objects (in package stats
stats::ts
because is saw from help that forecasts use a package called stats ;)
forecast::ts
Time-Series Objects
(in package stats
was giving me error, because forecast package was using a sub package ;
so final usage looks like this :
library(bReeze)
library(forecast)
# Subset data
my_time_series <- stats::ts(c(df_sub$y), start=2018, frequency = 12)
# Plot
theme_set(theme_classic())
ggseasonplot(my_time_series) + labs(title="My graph title")
library(chron)
is.weekend.chron <- is.weekend
library(tseries)
then you can call is.weekend for the tseries version or is.weekend.chron for the chron version
you should turn to the conflicted
package from Hadly.
library(conflicted)
library(dplyr)
filter(mtcars, am & cyl == 8)
Then the conflicted package will throw an error and will force you clearly determine which function you prefer:
Error: filter found in 2 packages. You must indicate which one you want with :: * dplyr::filter * stats::filter
To resolve conflicts for your entire session, use <-
:
filter <- dplyr::filter
filter(mtcars, am & cyl == 8)
mpg cyl disp hp drat wt qsec vs am gear carb
1 15.8 8 351 264 4.22 3.17 14.5 0 1 5 4
2 15.0 8 301 335 3.54 3.57 14.6 0 1 5 8
You can also turn to the conflict_prefer()
function which can determine the winner when a conflict occur.
The code example is borrowed from Hadly, pls refer to the package website.
https://www.tidyverse.org/blog/2018/06/conflicted/