Convert a RGB Color Value to a Hexadecimal String

Question

In my Java application, I was able to get the Color of a JButton in terms of red, green and blue; I have stored these values in three int

Answer 1

This is an adapted version of the answer given by Vivien Barousse with the update from Vulcan applied. In this example I use sliders to dynamically retreive the RGB values from three sliders and display that color in a rectangle. Then in method toHex() I use the values to create a color and display the respective Hex color code.

This example does not include the proper constraints for the GridBagLayout. Though the code will work, the display will look strange.

public class HexColor
{

  public static void main (String[] args)
  {
   JSlider sRed = new JSlider(0,255,1);
   JSlider sGreen = new JSlider(0,255,1);
   JSlider sBlue = new JSlider(0,255,1);
   JLabel hexCode = new JLabel();
   JPanel myPanel = new JPanel();
   GridBagLayout layout = new GridBagLayout();
   JFrame frame = new JFrame();

   //set frame to organize components using GridBagLayout 
   frame.setLayout(layout);

   //create gray filled rectangle 
   myPanel.paintComponent();
   myPanel.setBackground(Color.GRAY);

   //In practice this code is replicated and applied to sGreen and sBlue. 
   //For the sake of brevity I only show sRed in this post.
   sRed.addChangeListener(
         new ChangeListener()
         {
             @Override
             public void stateChanged(ChangeEvent e){
                 myPanel.setBackground(changeColor());
                 myPanel.repaint();
                 hexCode.setText(toHex());
         }
         }
     );
   //add each component to JFrame
   frame.add(myPanel);
   frame.add(sRed);
   frame.add(sGreen);
   frame.add(sBlue);
   frame.add(hexCode);
} //end of main

  //creates JPanel filled rectangle
  protected void paintComponent(Graphics g)
  {
      super.paintComponent(g);
      g.drawRect(360, 300, 10, 10);
      g.fillRect(360, 300, 10, 10);
  }

  //changes the display color in JPanel
  private Color changeColor()
  {
    int r = sRed.getValue();
    int b = sBlue.getValue();
    int g = sGreen.getValue();
    Color c;
    return  c = new Color(r,g,b);
  }

  //Displays hex representation of displayed color
  private String toHex()
  {
      Integer r = sRed.getValue();
      Integer g = sGreen.getValue();
      Integer b = sBlue.getValue();
      Color hC;
      hC = new Color(r,g,b);
      String hex = Integer.toHexString(hC.getRGB() & 0xffffff);
      while(hex.length() < 6){
          hex = "0" + hex;
      }
      hex = "Hex Code: #" + hex;
      return hex;
  }
}

A huge thank you to both Vivien and Vulcan. This solution works perfectly and was super simple to implement.

Answer 2

A one liner but without String.format for all RGB colors:

Color your_color = new Color(128,128,128);

String hex = "#"+Integer.toHexString(your_color.getRGB()).substring(2);

You can add a .toUpperCase()if you want to switch to capital letters. Note, that this is valid (as asked in the question) for all RGB colors.

When you have ARGB colors you can use:

Color your_color = new Color(128,128,128,128);

String buf = Integer.toHexString(your_color.getRGB());
String hex = "#"+buf.substring(buf.length()-6);

A one liner is theoretically also possible but would require to call toHexString twice. I benchmarked the ARGB solution and compared it with String.format():

Answer 3

You can use

String hex = String.format("#%02x%02x%02x", r, g, b);  

Use capital X's if you want your resulting hex-digits to be capitalized (#FFFFFF vs. #ffffff).

Answer 4

Random ra = new Random();
int r, g, b;
r=ra.nextInt(255);
g=ra.nextInt(255);
b=ra.nextInt(255);
Color color = new Color(r,g,b);
String hex = Integer.toHexString(color.getRGB() & 0xffffff);
if (hex.length() < 6) {
    hex = "0" + hex;
}
hex = "#" + hex;