How to convert a time string to seconds?

Question

I need to convert time value strings given in the following format to seconds, for example:

1.\'00:00:00,000\' -> 0 seconds

2.\'00:00:10,000\' -> 10 s         


        

Answer 1

import time
from datetime import datetime

t1 = datetime.now().replace(microsecond=0)
time.sleep(3)
now = datetime.now().replace(microsecond=0)
print((now - t1).total_seconds())

result: 3.0

Answer 2

There is always parsing by hand

>>> import re
>>> ts = ['00:00:00,000', '00:00:10,000', '00:01:04,000', '01:01:09,000']
>>> for t in ts:
...     times = map(int, re.split(r"[:,]", t))
...     print t, times[0]*3600+times[1]*60+times[2]+times[3]/1000.
... 
00:00:00,000 0.0
00:00:10,000 10.0
00:01:04,000 64.0
01:01:09,000 3669.0
>>> 

Answer 3

without imports

time = "01:34:11"
sum(x * int(t) for x, t in zip([3600, 60, 1], time.split(":"))) 

Answer 4

It looks like you're willing to strip fractions of a second... the problem is you can't use '00' as the hour with %I

>>> time.strptime('00:00:00,000'.split(',')[0],'%H:%M:%S')
time.struct_time(tm_year=1900, tm_mon=1, tm_mday=1, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=0, tm_yday=1, tm_isdst=-1)
>>>

Answer 5

A little more pythonic way I think would be:

timestr = '00:04:23'

ftr = [3600,60,1]

sum([a*b for a,b in zip(ftr, map(int,timestr.split(':')))])

Output is 263Sec.

I would be interested to see if anyone could simplify it further.

Answer 6

Inspired by sverrir-sigmundarson's comment:

def time_to_sec(time_str):
    return sum(x * int(t) for x, t in zip([1, 60, 3600], reversed(time_str.split(":"))))