Determine whether an array contains a value [duplicate]

Answer 1

jQuery has a utility function for this:

$.inArray(value, array)

Returns index of value in array. Returns -1 if array does not contain value.

See also How do I check if an array includes an object in JavaScript?

Answer 2

This is generally what the indexOf() method is for. You would say:

return arrValues.indexOf('Sam') > -1

Answer 3

The simplest solution for a contains function, would be a function that looks like this :

var contains = function (haystack, needle) {
    return !!~haystack.indexOf(needle);
}

Ideally, you wouldn't make this a stand-alone function, though, but part of a helper library :

var helper = {};

helper.array = {
    contains : function (haystack, needle) {
        return !!~haystack.indexOf(needle);
    }, 
    ...
};

Now, if you happen to be one of those unlucky people who still needs to support IE<9 and thus can't rely on indexOf, you could use this polyfill, which I got from the MDN :

if (!Array.prototype.indexOf) {
  Array.prototype.indexOf = function(searchElement, fromIndex) {
    var k;
    if (this == null) {
      throw new TypeError('"this" is null or not defined');
    }
    var o = Object(this);
    var len = o.length >>> 0;
    if (len === 0) {
      return -1;
    }
    var n = +fromIndex || 0;

    if (Math.abs(n) === Infinity) {
      n = 0;
    }
    if (n >= len) {
      return -1;
    }
    k = Math.max(n >= 0 ? n : len - Math.abs(n), 0);
    while (k < len) {
      if (k in o && o[k] === searchElement) {
        return k;
      }
      k++;
    }
    return -1;
  };
}

Answer 4

function setFound(){   
 var l = arr.length, textBox1 = document.getElementById("text1");
    for(var i=0; i<l;i++)
    {
     if(arr[i]==searchele){
      textBox1 .value = "Found";
      return;
     }
    }
    textBox1 .value = "Not Found";
return;
}

This program checks whether the given element is found or not. Id text1 represents id of textbox and searchele represents element to be searched (got fron user); if you want index, use i value

Answer 5

var contains = function(needle) {
    // Per spec, the way to identify NaN is that it is not equal to itself
    var findNaN = needle !== needle;
    var indexOf;

    if(!findNaN && typeof Array.prototype.indexOf === 'function') {
        indexOf = Array.prototype.indexOf;
    } else {
        indexOf = function(needle) {
            var i = -1, index = -1;

            for(i = 0; i < this.length; i++) {
                var item = this[i];

                if((findNaN && item !== item) || item === needle) {
                    index = i;
                    break;
                }
            }

            return index;
        };
    }

    return indexOf.call(this, needle) > -1;
};

You can use it like this:

var myArray = [0,1,2],
    needle = 1,
    index = contains.call(myArray, needle); // true

CodePen validation/usage

Answer 6

Using array .map function that executes a function for every value in an array seems cleanest to me.

Ref: Array.prototype.map()

This method can work well both for simple arrays and for arrays of objects where you need to see if a key/value exists in an array of objects.

function inArray(myArray,myValue){
    var inArray = false;
    myArray.map(function(key){
        if (key === myValue){
            inArray=true;
        }
    });
    return inArray;
};

var anArray = [2,4,6,8]
console.log(inArray(anArray, 8)); // returns true
console.log(inArray(anArray, 1)); // returns false

function inArrayOfObjects(myArray,myValue,objElement){
    var inArray = false;
    myArray.map(function(arrayObj){
        if (arrayObj[objElement] === myValue) {
            inArray=true;
        }
    });
    return inArray;
};

var objArray = [{id:4,value:'foo'},{id:5,value:'bar'}]
console.log(inArrayOfObjects(objArray, 4, 'id')); // returns true
console.log(inArrayOfObjects(objArray, 'bar', 'value')); // returns true
console.log(inArrayOfObjects(objArray, 1, 'id')); // returns false