scipy.sparse.linalg.LinearOperator with optional keyword argument

后端 未结 0 631
有刺的猬
有刺的猬 2020-11-29 23:23

I would like to create a linear operator with scipy.sparse.linalg.LinearOperator from a function which has an optional keyword argument, e.g myfunc(x,y=0)

相关标签:
回答
  • 消灭零回复
提交回复
热议问题