How can I get the class name from a C++ object?

Question

Is it possible to get the object name too?

#include

class one {
public:
    int no_of_students;
    one() { no_of_students = 0; }
    void new         


        

Answer 1

Just write simple template:

template<typename T>
const char* getClassName(T) {
  return typeid(T).name();
}

struct A {} a;

void main() {
   std::cout << getClassName(a);
}

Answer 2

use typeid(class).name

// illustratory code assuming all includes/namespaces etc

#include <iostream>
#include <typeinfo>
using namespace std;

struct A{};
int main(){
   cout << typeid(A).name();
}

It is important to remember that this gives an implementation defined names.

As far as I know, there is no way to get the name of the object at run time reliably e.g. 'A' in your code.

EDIT 2:

#include <typeinfo>
#include <iostream>
#include <map>
using namespace std; 

struct A{
};
struct B{
};

map<const type_info*, string> m;

int main(){
    m[&typeid(A)] = "A";         // Registration here
    m[&typeid(B)] = "B";         // Registration here

    A a;
    cout << m[&typeid(a)];
}