dump all mysql tables into separate files automagically?

Question

I\'d like to get dumps of each mysql table into separate files. The manual indicates that the syntax for this is

mysqldump [options] db_name [tbl_name ...]
         


        

Answer 1

You can accomplish this by:

1. Get the list of databases in mysql
2. dump each database with mysqldump

# Optional variables for a backup script
MYSQL_USER="root"
MYSQL_PASS="something"
BACKUP_DIR=/srv/backup/$(date +%Y-%m-%dT%H_%M_%S);
test -d "$BACKUP_DIR" || mkdir -p "$BACKUP_DIR"
# Get the database list, exclude information_schema
for db in $(mysql -B -s -u $MYSQL_USER --password=$MYSQL_PASS -e 'show databases' | grep -v information_schema)
do
  # dump each database in a separate file
  mysqldump -u $MYSQL_USER --password=$MYSQL_PASS "$db" | gzip > "$BACKUP_DIR/$db.sql.gz"
done

Answer 2

I'm not bash master, but I'd just do it with a bash script. Without hitting MySQL, with knowledge of the data directory and database name, you could just scan for all .frm files (one for every table in that db/directory) for a list of tables.

I'm sure there are ways to make it slicker and accept arguments or whatnot, but this worked well for me.

tables_in_a_db_to_sql.sh

#!/bin/bash

database="this_is_my_database"
datadir="/var/lib/mysql/"
datadir_escaped="\/var\/lib\/mysql\/"

all_tables=($(ls $datadir$database/*.frm | sed s/"$datadir_escaped$database\/"/""/g | sed s/.frm//g))

for t in "${all_tables[@]}"; do
        outfile=$database.$t.sql
        echo "-- backing up $t to $outfile"
        echo "mysqldump [options] $database $t > $outfile"
        # mysqldump [options] $database $t > $outfile
done

Fill in the [options] and desired outfile convention as you need, and uncomment the last mysqldump line.

Answer 3

Here's a script that dumps table data as SQL commands into separate, compressed files. It does not require being on the MySQL server host, doesn't hard-code the password in the script, and is just for a specific db, not all db's on the server:

#!/bin/bash

# dump-tables-mysql.sh
# Descr: Dump MySQL table data into separate SQL files for a specified database.
# Usage: Run without args for usage info.
# Author: @Trutane
# Ref: http://stackoverflow.com/q/3669121/138325
# Notes:
#  * Script will prompt for password for db access.
#  * Output files are compressed and saved in the current working dir, unless DIR is
#    specified on command-line.

[ $# -lt 3 ] && echo "Usage: $(basename $0) <DB_HOST> <DB_USER> <DB_NAME> [<DIR>]" && exit 1

DB_host=$1
DB_user=$2
DB=$3
DIR=$4

[ -n "$DIR" ] || DIR=.
test -d $DIR || mkdir -p $DIR

echo -n "DB password: "
read -s DB_pass
echo
echo "Dumping tables into separate SQL command files for database '$DB' into dir=$DIR"

tbl_count=0

for t in $(mysql -NBA -h $DB_host -u $DB_user -p$DB_pass -D $DB -e 'show tables') 
do 
    echo "DUMPING TABLE: $DB.$t"
    mysqldump -h $DB_host -u $DB_user -p$DB_pass $DB $t | gzip > $DIR/$DB.$t.sql.gz
    tbl_count=$(( tbl_count + 1 ))
done

echo "$tbl_count tables dumped from database '$DB' into dir=$DIR"

Answer 4

See the following article by Pauli Marcus:

Howto split a SQL database dump into table-wise files

Splitting a sql file containing a whole database into per-table files is quite easy: Grep the .sql for any occurence of DROP TABLE. Generate the file name from the table name that is included in the DROP TABLE statement. Echo the output to a file. Here is a little script that expects a .sql file as input:

#!/bin/bash

file=$1 # the input file
directory="$file-splitted" # the output directory
output="$directory/header" # the first file containing the header
GREP="DROP TABLE" # what we are looking for

mkdir $directory # create the output directory

while read line
do
   # if the current line contains the wanted statement
   if [ $(echo "$line" | grep -c "$GREP") == "1" ]
   then
      # extract the file name
      myfile=$(echo $line | awk '{print $5}' | sed -e 's/`//g' -e 's/;//g')
      # set the new file name
      output="$directory/$myfile"
   fi
       echo "$line" >> $output # write to file
done < $file

Answer 5

If You want to dump all tables from all databases just combine Elias Torres Arroyo's and Trutane's answer: And if You don't want to give Your password on terminal, just store Your password in an extra config file (chmod 0600)- see Mysqldump launched by cron and password security

#!/bin/bash

# this file
# a) gets all databases from mysql
# b) gets all tables from all databases in a)
# c) creates subfolders for every database in a)
# d) dumps every table from b) in a single file

    # this is a mixture of scripts from Trutane (http://stackoverflow.com/q/3669121/138325) 
    # and Elias Torres Arroyo (https://stackoverflow.com/a/14711298/8398149)

# usage: 
# sk-db.bash parameters
# where pararmeters are:

# d "dbs to leave"
# t " tables to leave"
# u "user who connects to database"
# h "db host"
# f "/backup/folder"



user='root'
host='localhost'
backup_folder=''
leave_dbs=(information_schema mysql)
leave_tables=()
while getopts ":d:t:u:h:f:" opt; do
  case $opt in
    d) leave_dbs=( $OPTARG )
    ;;
    t) leave_tables=( $OPTARG )
    ;;
    u) user=$OPTARG
    ;;
    h) host=$OPTARG
    ;;
    f) backup_folder=$OPTARG
    ;;

    \?) echo "Invalid option -$OPTARG" >&2
    ;;
  esac
done
echo '****************************************'
echo "Database Backup with these options"
echo "Host $host"
echo "User $user"
echo "Backup in $backup_folder"
echo '----------------------------------------'
echo "Databases to emit:"
printf "%s\n" "${leave_dbs[@]}"
echo '----------------------------------------'
echo "Tables to emit:"
printf "%s\n" "${leave_tables[@]}"
echo '----------------------------------------'


BACKUP_DIR=$backup_folder/$(date +%Y-%m-%dT%H_%M_%S);
CONFIG_FILE=/root/db-config.cnf

function contains() {
    local n=$#
    local value=${!n}
    for ((i=1;i < $#;i++)) {
        if [ "${!i}" == "${value}" ]; then
            echo "y"
            return 0
        fi
    }
    echo "n"
    return 1
}


test -d "$BACKUP_DIR" || mkdir -p "$BACKUP_DIR"
# Get the database list, exclude information_schema
database_count=0
tbl_count=0

for db in $(mysql --defaults-extra-file=$CONFIG_FILE -B -s -u $user -e 'show databases' )
do
    if [ $(contains "${leave_dbs[@]}" "$db") == "y" ]; then
        echo "leave database $db as requested"
    else

       # dump each database in a separate file
       (( database_count++ ))
       DIR=$BACKUP_DIR/$db
       [ -n "$DIR" ] || DIR=.

       test -d $DIR || mkdir -p $DIR

       echo
       echo "Dumping tables into separate SQL command files for database '$db' into dir=$DIR"

       for t in $(mysql --defaults-extra-file=$CONFIG_FILE -NBA -h $host -u $user -D $db -e 'show tables')
       do
           if [ $(contains "${leave_tables[@]}" "$db.$t") == "y" ]; then
               echo "leave table $db.$t as requested"
           else
               echo "DUMPING TABLE: $db.$t"
  #            mysqldump --defaults-extra-file=$CONFIG_FILE -h $host -u $user $db $t  > $DIR/$db.$t.sql
               tbl_count=$(( tbl_count + 1 ))
           fi
       done

       echo "Database $db is finished"
       echo '----------------------------------------'

    fi
done
echo '----------------------------------------'
echo "Backup completed"
echo '**********************************************'

And also, this helped:

Check if bash array contains value

arrays in bash

named arguments in script

Answer 6

Here is the corresponding import.

#!/bin/bash

# import-files-mysql.sh
# Descr: Import separate SQL files for a specified database.
# Usage: Run without args for usage info.
# Author: Will Rubel
# Notes:
#  * Script will prompt for password for db access.

[ $# -lt 3 ] && echo "Usage: $(basename $0) <DB_HOST> <DB_USER> <DB_NAME> [<DIR>]" && exit 1

DB_host=$1
DB_user=$2
DB=$3
DIR=$4

DIR=$DIR/*


echo -n "DB password: "
read -s DB_pass
echo
echo "Importing separate SQL command files for database '$DB' into '$DB'"

file_count=0


for f in $DIR

do 
    echo "IMPORTING FILE: $f"

    gunzip -c $f | mysql -h $DB_host -u $DB_user -p$DB_pass $DB

    (( file_count++ ))
done

echo "$file_count files importing to database '$DB'"