How to verify element present or visible in selenium 2 (Selenium WebDriver)

Question

Any one can send me sample code how to verify element

1. ispresent
   
2. isvisible
   
3. isenable
   
4. textpresent
   

in Se

Answer 1

Here is my Java code for Selenium WebDriver. Write the following method and call it during assertion:

protected boolean isElementPresent(By by){
        try{
            driver.findElement(by);
            return true;
        }
        catch(NoSuchElementException e){
            return false;
        }
    }

Answer 2

webDriver.findElement(By.xpath("//*[@id='element']")).isDisplayed();

Answer 3

I used java print statements for easy understanding.

1. To check Element Present:

   if(driver.findElements(By.xpath("value")).size() != 0){
   System.out.println("Element is Present");
   }else{
   System.out.println("Element is Absent");
   }
   

   Or

   if(driver.findElement(By.xpath("value"))!= null){
   System.out.println("Element is Present");
   }else{
   System.out.println("Element is Absent");
   }
   

2. To check Visible:

   if( driver.findElement(By.cssSelector("a > font")).isDisplayed()){
   System.out.println("Element is Visible");
   }else{
   System.out.println("Element is InVisible");
   }
   

3. To check Enable:

   if( driver.findElement(By.cssSelector("a > font")).isEnabled()){
   System.out.println("Element is Enable");
   }else{
   System.out.println("Element is Disabled");
   }
   

4. To check text present

   if(driver.getPageSource().contains("Text to check")){
   System.out.println("Text is present");
   }else{
   System.out.println("Text is absent");
   }
   

Answer 4

Try using below code:

private enum ElementStatus{
        VISIBLE,
        NOTVISIBLE,
        ENABLED,
        NOTENABLED,
        PRESENT,
        NOTPRESENT
    }
    private ElementStatus isElementVisible(WebDriver driver, By by,ElementStatus getStatus){
        try{
            if(getStatus.equals(ElementStatus.ENABLED)){
                if(driver.findElement(by).isEnabled())
                    return ElementStatus.ENABLED;
                return ElementStatus.NOTENABLED; 
            }
            if(getStatus.equals(ElementStatus.VISIBLE)){
                if(driver.findElement(by).isDisplayed())
                    return ElementStatus.VISIBLE;
                return ElementStatus.NOTVISIBLE;
            }
            return ElementStatus.PRESENT;
        }catch(org.openqa.selenium.NoSuchElementException nse){
            return ElementStatus.NOTPRESENT;
        }
    }

Answer 5

To make sure that an element is present you can do the following:

driver.findElements(By.id("id"));

That will return an array, if that array size is > 0 then the element/s is present.

Also, you need to provide more information, such as language and what have you tried before asking,

Good luck

Answer 6

To check if element is visible we need to use element.isDisplayed(); But if we need to check for presence of element anywhere in Dom we can use following method

public boolean isElementPresentCheckUsingJavaScriptExecutor(WebElement element) {
        JavascriptExecutor jse=(JavascriptExecutor) driver;
        try {
            Object obj = jse.execute("return typeof(arguments[0]) != 'undefined' && arguments[0] != null;",
                    element);
            if (obj.toString().contains("true")) {
                System.out.println("isElementPresentCheckUsingJavaScriptExecutor: SUCCESS");
                return true;
            } else {
                System.out.println("isElementPresentCheckUsingJavaScriptExecutor: FAIL");
            }

        } catch (NoSuchElementException e) {
            System.out.println("isElementPresentCheckUsingJavaScriptExecutor: FAIL");
        }
        return false;
    }