Get current domain

Question

I have my site on the server http://www.myserver.uk.com.

On this server I have two domains:

one.com and two.com

I would l

Answer 1

Try $_SERVER['SERVER_NAME'].

Tips: Create a PHP file that calls the function phpinfo() and see the "PHP Variables" section. There are a bunch of useful variables we never think of there.

Answer 2

Using $_SERVER['HTTP_HOST'] gets me (subdomain.)maindomain.extension. It seems like the easiest solution to me.

If you're actually 'redirecting' through an iFrame, you could add a GET parameter which states the domain.

<iframe src="myserver.uk.com?domain=one.com"/>

And then you could set a session variable that persists this data throughout your application.

Answer 3

The best use would be

echo $_SERVER['HTTP_HOST'];

And it can be used like this:

if (strpos($_SERVER['HTTP_HOST'], 'banana.com') !== false) {
    echo "Yes this is indeed the banana.com domain";
}

This code below is a good way to see all the variables in $_SERVER in a structured HTML output with your keywords highlighted that halts directly after execution. Since I do sometimes forget which one to use myself - I think this can be nifty.

<?php
    // Change banana.com to the domain you were looking for..
    $wordToHighlight = "banana.com";
    $serverVarHighlighted = str_replace( $wordToHighlight, '<span style=\'background-color:#883399; color: #FFFFFF;\'>'. $wordToHighlight .'</span>',  $_SERVER );
    echo "<pre>";
    print_r($serverVarHighlighted);
    echo "</pre>";
    exit();
?>

Answer 4

Everybody is using the parse_url function, but sometimes user may pass the argumet in different format.

So as to fix that, I have created the function. Check this out:

function fixDomainName($url='')
{
    $strToLower = strtolower(trim($url));
    $httpPregReplace = preg_replace('/^http:\/\//i', '', $strToLower);
    $httpsPregReplace = preg_replace('/^https:\/\//i', '', $httpPregReplace);
    $wwwPregReplace = preg_replace('/^www\./i', '', $httpsPregReplace);
    $explodeToArray = explode('/', $wwwPregReplace);
    $finalDomainName = trim($explodeToArray[0]);
    return $finalDomainName;
}

Just pass the URL and get the domain.

For example,

echo fixDomainName('https://stackoverflow.com');

will return the result will be

stackoverflow.com

And in some situation:

echo fixDomainName('stackoverflow.com/questions/id/slug');

And it will also return stackoverflow.com.

Answer 5

I know this might not be entirely on the subject, but in my experience, I find storing WWW-ness of current URL in a variable useful.

Edit: In addition, please see my comment below, to see what this is getting at.

This is important when determining whether to dispatch Ajax calls with "www", or without:

$.ajax("url" : "www.site.com/script.php", ...

$.ajax("url" : "site.com/script.php", ...

When dispatching an Ajax call the domain name must match that of in the browser's address bar, otherwise you will have Uncaught SecurityError in console.

So I came up with this solution to address the issue:

<?php
    substr($_SERVER['SERVER_NAME'], 0, 3) == "www" ? $WWW = true : $WWW = false;

    if ($WWW) {
        /* We have www.example.com */
    } else {
        /* We have example.com */
    }
?>

Then, based on whether $WWW is true, or false run the proper Ajax call.

I know this might sound trivial, but this is such a common problem that is easy to trip over.

Answer 6

Try using this: $_SERVER['SERVER_NAME']

Or parse

$_SERVER['REQUEST_URI']

apache_request_headers()