Print second last column/field in awk

Question

I want to print the second last column or field in awk. The number of fields is variable. I know that I should be able to use $NF but not sure how it can be use

Answer 1

You weren't far from the result! This does it:

awk '{NF--; print $NF}' file

This decrements the number of fields in one, so that $NF contains the former penultimate.

Test

Let's generate some numbers and print them on groups of 5:

$ seq 12 | xargs -n5
1 2 3 4 5
6 7 8 9 10
11 12

Let's print the penultimate on each line:

$ seq 12 | xargs -n5 | awk '{NF--; print $NF}'
4
9
11

Answer 2

Perl solution similar to Chris Kannon's awk solution:

perl -lane 'print $F[$#F-1]' file

These command-line options are used:

• n loop around every line of the input file, do not automatically print every line

• l removes newlines before processing, and adds them back in afterwards

• a autosplit mode – split input lines into the @F array. Defaults to splitting on whitespace

• e execute the perl code

The @F autosplit array starts at index [0] while awk fields start with $1.
$#F is the number of elements in @F

Answer 3

First decrements the value and then print it -

awk ' { print $(--NF)}' file

OR

rev file|cut -d ' ' -f2|rev

Answer 4

Small addition to Chris Kannon' accepted answer: only print if there actually is a second last column.

(
echo       | awk 'NF && NF-1 { print ( $(NF-1) ) }'
echo 1     | awk 'NF && NF-1 { print ( $(NF-1) ) }'
echo 1 2   | awk 'NF && NF-1 { print ( $(NF-1) ) }'
echo 1 2 3 | awk 'NF && NF-1 { print ( $(NF-1) ) }'
)

Answer 5

It's simplest:

 awk '{print $--NF}' 

The reason the original $NF-- didn't work is because the expression is evaluated before the decrement, whereas my prefix decrement is performed before evaluation.

Answer 6

If you have many columns and want to print all but not the three cloumns in the last, then this might help

awk '{ $NF="";$(NF-1)="";$(NF-2)="" ; print $0 }'