Call Python script from bash with argument

Question

I know that I can run a python script from my bash script using the following:

python python_script.py

But what about if I wanted to pass a

Answer 1

and take a look at the getopt module. It works quite good for me!

Answer 2

To execute a python script in a bash script you need to call the same command that you would within a terminal. For instance

> python python_script.py var1 var2

To access these variables within python you will need

import sys
print sys.argv[0] # prints python_script.py
print sys.argv[1] # prints var1
print sys.argv[2] # prints var2

Answer 3

use in the script:

echo $(python python_script.py arg1 arg2) > /dev/null

or

python python_script.py "string arg"  > /dev/null

The script will be executed without output.

Answer 4

I have a bash script that calls a small python routine to display a message window. As I need to use killall to stop the python script I can't use the above method as it would then mean running killall python which could take out other python programmes so I use

pythonprog.py "$argument" & # The & returns control straight to the bash script so must be outside the backticks. The preview of this message is showing it without "`" either side of the command for some reason.

As long as the python script will run from the cli by name rather than python pythonprog.py this works within the script. If you need more than one argument just use a space between each one within the quotes.

Answer 5

Print all args without the filename:

for i in range(1, len(sys.argv)):
print(sys.argv[i])

Answer 6

Use

python python_script.py filename

and in your Python script

import sys
print sys.argv[1]