I have a dataframe with 2 index levels:
value
Trial measurement
1 0 13
1 3
The reset_index() is a pandas DataFrame method that will transfer index values into the DataFrame as columns. The default setting for the parameter is drop=False (which will keep the index values as columns).
All you have to do add .reset_index(inplace=True)
after the name of the DataFrame:
df.reset_index(inplace=True)
As @cs95 mentioned in a comment, to drop only one level, use:
df.reset_index(level=[...])
This avoids having to redefine your desired index after reset.
I ran into Karl's issue as well. I just found myself renaming the aggregated column then resetting the index.
df = pd.DataFrame(df.groupby(['arms', 'success'])['success'].sum()).rename(columns={'success':'sum'})
df = df.reset_index()
This doesn't really apply to your case but could be helpful for others (like myself 5 minutes ago) to know. If one's multindex have the same name like this:
value
Trial Trial
1 0 13
1 3
2 4
2 0 NaN
1 12
3 0 34
df.reset_index(inplace=True)
will fail, cause the columns that are created cannot have the same names.
So then you need to rename the multindex with df.index = df.index.set_names(['Trial', 'measurement'])
to get:
value
Trial measurement
1 0 13
1 1 3
1 2 4
2 0 NaN
2 1 12
3 0 34
And then df.reset_index(inplace=True)
will work like a charm.
I encountered this problem after grouping by year and month on a datetime-column(not index) called live_date
, which meant that both year and month were named live_date
.
There may be situations when df.reset_index()
cannot be used (e.g., when you need the index, too). In this case, use index.get_level_values()
to access index values directly:
df['Trial'] = df.index.get_level_values(0)
df['measurement'] = df.index.get_level_values(1)
This will assign index values to individual columns and keep the index.
See the docs for further info.