Java: how to convert HashMap to array

Question

I need to convert a HashMap to an array; could anyone show me how it\'s done?

Answer 1

If you have HashMap<String, SomeObject> hashMap then:

hashMap.values().toArray();

Will return an Object[]. If instead you want an array of the type SomeObject, you could use:

hashMap.values().toArray(new SomeObject[0]);

Answer 2

I used almost the same as @kmccoy, but instead of a keySet() I did this

hashMap.values().toArray(new MyObject[0]);

Answer 3

hashMap.keySet().toArray(); // returns an array of keys
hashMap.values().toArray(); // returns an array of values

---

Edit

It should be noted that the ordering of both arrays may not be the same, See oxbow_lakes answer for a better approach for iteration when the pair key/values are needed.

Answer 4

@SuppressWarnings("unchecked")
    public static <E,T> E[] hashMapKeysToArray(HashMap<E,T> map)
    {
        int s;
        if(map == null || (s = map.size())<1)
            return null;

        E[] temp;
        E typeHelper;
        try
        {
            Iterator<Entry<E, T>> iterator = map.entrySet().iterator();
            Entry<E, T> iK = iterator.next();
            typeHelper = iK.getKey();

            Object o = Array.newInstance(typeHelper.getClass(), s);
            temp = (E[]) o;

            int index = 0;
            for (Map.Entry<E,T> mapEntry : map.entrySet())
            {
                temp[index++] = mapEntry.getKey();
            }
        }
        catch (Exception e)
        {
            return null;
        }
        return temp;
    }
//--------------------------------------------------------
    @SuppressWarnings("unchecked")
    public static <E,T> T[] hashMapValuesToArray(HashMap<E,T> map)
    {
        int s;
        if(map == null || (s = map.size())<1)
            return null;

        T[] temp;
        T typeHelper;
        try
        {
            Iterator<Entry<E, T>> iterator = map.entrySet().iterator();
            Entry<E, T> iK = iterator.next();
            typeHelper = iK.getValue();

            Object o = Array.newInstance(typeHelper.getClass(), s);
            temp = (T[]) o;

            int index = 0;
            for (Map.Entry<E,T> mapEntry : map.entrySet())
            {
                temp[index++] = mapEntry.getValue();
            }
        }
        catch (Exception e)
        {return null;}

        return temp;
    }

Answer 5

If you are using Java 8+ and need a 2 dimensional Array, perhaps for TestNG data providers, you can try:

map.entrySet()
    .stream()
    .map(e -> new Object[]{e.getKey(), e.getValue()})
    .toArray(Object[][]::new);

If your Objects are Strings and you need a String[][], try:

map.entrySet()
    .stream()
    .map(e -> new String[]{e.getKey(), e.getValue().toString()})
    .toArray(String[][]::new);

Answer 6

To guarantee the correct order for each array of Keys and Values, use this (the other answers use individual Sets which offer no guarantee as to order.

Map<String, Object> map = new HashMap<String, Object>();
String[] keys = new String[map.size()];
Object[] values = new Object[map.size()];
int index = 0;
for (Map.Entry<String, Object> mapEntry : map.entrySet()) {
    keys[index] = mapEntry.getKey();
    values[index] = mapEntry.getValue();
    index++;
}