PHP extract GPS EXIF data

Question

I would like to extract the GPS EXIF tag from pictures using php. I\'m using the exif_read_data() that returns a array of all tags + data :

GPS.         


        

Answer 1

This is a refactored version of Gerald Kaszuba's code (currently the most widely accepted answer). The result should be identical, but I've made several micro-optimizations and combined the two separate functions into one. In my benchmark testing, this version shaved about 5 microseconds off the runtime, which is probably negligible for most applications, but might be useful for applications which involve a large number of repeated calculations.

$exif = exif_read_data($filename);
$latitude = gps($exif["GPSLatitude"], $exif['GPSLatitudeRef']);
$longitude = gps($exif["GPSLongitude"], $exif['GPSLongitudeRef']);

function gps($coordinate, $hemisphere) {
  if (is_string($coordinate)) {
    $coordinate = array_map("trim", explode(",", $coordinate));
  }
  for ($i = 0; $i < 3; $i++) {
    $part = explode('/', $coordinate[$i]);
    if (count($part) == 1) {
      $coordinate[$i] = $part[0];
    } else if (count($part) == 2) {
      $coordinate[$i] = floatval($part[0])/floatval($part[1]);
    } else {
      $coordinate[$i] = 0;
    }
  }
  list($degrees, $minutes, $seconds) = $coordinate;
  $sign = ($hemisphere == 'W' || $hemisphere == 'S') ? -1 : 1;
  return $sign * ($degrees + $minutes/60 + $seconds/3600);
}